So, ≈ 0.577 Vpk
A square wave will have the highest value since it has a peak, positive or negative, all of the time. Other wave shapes such as triangular and sine, have a lower value than this.
All AC voltages and currents are quoted as root-mean-square (rms) values where, for a sinusoidal waveform, the rms value is 0.707 Vmax or 0.707 Imax.From this, you can determine the value of the amplitude Vmax or Imax:Vmax = Vrms/0.707 or Imax = Irms/0.707Once you know the value of the amplitude (Vmax or Imax), simply double it to determine the peak-to-peak value.
Voltage and frequency are independent quantities.AnswerBecause the r.m.s. value is dependent on the shape of the waveform, not its frequency. The average value of any symmetrical waveform is zero and is independent of frequency.
okay, where's the "given waveform"?
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
A square wave will have the highest value since it has a peak, positive or negative, all of the time. Other wave shapes such as triangular and sine, have a lower value than this.
rms value is measured using voltmeter with the use of heat sensing elements.
All AC voltages and currents are quoted as root-mean-square (rms) values where, for a sinusoidal waveform, the rms value is 0.707 Vmax or 0.707 Imax.From this, you can determine the value of the amplitude Vmax or Imax:Vmax = Vrms/0.707 or Imax = Irms/0.707Once you know the value of the amplitude (Vmax or Imax), simply double it to determine the peak-to-peak value.
Voltage and frequency are independent quantities.AnswerBecause the r.m.s. value is dependent on the shape of the waveform, not its frequency. The average value of any symmetrical waveform is zero and is independent of frequency.
okay, where's the "given waveform"?
Hi, RMS is voltage X .707 and the power is voltage X current. Hope that helps, Cubby
There is such a thing as "RMS power", but it's not useful for anything, so don't use the term. No one measures the RMS of the power waveform. What they do is measure the RMS of a voltage waveform, and then use that to derive the averagepower. The correct term is "average power", not "RMS power". You could measure the RMS of the power waveform instead of the average, but your measurement would be 1.2 times too high.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
Multimeters measure AC in two primary ways... The older style meter uses a diode, capacitor, and resistor to measure the peak voltage of the AC signal. They then compensate their calibration to read in a close approximation of what the RMS value will be. Problem is that this only works well for true sinusoidal waveforms - if the waveform is triangular, for instance, the indicated value will not match the RMS value. The newer style meter, if it states that it is a true RMS meter, will sample the input waveform and actually calculate the RMS value. This is done by adding up the squares of the input, and then taking the square root of the result. That is a much better approximation of how much power the waveform can deliver.
Because your multimeter is not an adequate device for this kind of measurement. Use the correct multimeter to display the triangular wave value.
the number u are seeking is 0.639