You really need to know the line voltage (VL) involved. Provided the load is balanced, to find the line current, you need to divide the load (in watts) by (1.732 x VL). Incidentally, the correct symbol for kilowatts is kW, not Kw!
The formula you are looking for is I = W/E. Amps = Watts/Volts.
Current in 200kw at 480 volts = 200,000/480 = 416.667 amps
90 kW on 480 volts single phase would be 187.5 amps. On 480 v 3-phase it would be 108 amps.
A voltage of 240 volts is not a common three phase voltage. Single phase kva of 240 voltas and 50 amps is I x E/1000 = 240 x 50 = 12000/1000 = 12 kVa -- Assuming the 240 volts is phase to phase voltage, and this is a three phase application: KVA = V*I*sqrt (3) = 20.78KVA
You must rephrase your question to make it more specific. <<>> The formula to use to find KVA in a three phase system is, KVA = Amps x Volts x 1.73/1000.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
The maximum single phase HP motor listed in the CEC is 10 HP. At 115 volts 100 amps and 230 volts 50 amps.
75 Amps theoretically Need to know if the generator is 3 phase or single phase.
To calculate watts, you need to multiply the voltage (in volts) by the current (in amps). For the 208 volts, 8 amps heating element: Watts = 208 volts * 8 amps = 1664 watts For the 110 volts, 8 amps heating element: Watts = 110 volts * 8 amps = 880 watts
Using the formula: Amps = Watts/Volts look up the wire size needed in the national electric code book for the amperage of the device. This formula only works for single phase current. If you are using 3 phase, look in the book. In general, 15 Amps or less: 14 Ga Copper wire. 20 Amps or less 12 Ga. 30 Amps or less 10 Ga. Anything more than 30 amps, look it up in the book.
500,000 watts/240 volts = 2,083.34 Amps (single phase)
Amperes when kva is shown. The formula is, Amps = kva x 1000/1.73 x volts.
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
The equation that you are looking for is Amps = Watts/Volts. There are 6000 watts in 6kW.
if it's single-phase, 25,000 divided by 480.
A kw (kilowatt) is 1000 amps x volts. If you assume your one phase system has 120 volts, then divide by 120. Cheap, but close enough for most work, assume 100 volts, then each amp is a tenth of a kilowatt.
Power = volts times amps, so an appliance drawing 10 amps at a line voltage of 110 volts is consuming 1,100 watts. Keep in mind, however, that in a non purely resistive load, the phase angle of amps to volts might not be zero degrees, so the calculation becomes more complex, and depends on power factor, or phase angle.