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Different methods for different circuits. In a simple RC filter with a series R and shunt C, the time-constant T is equal to RC. The cutoff frequency is given by 1/(2.pi.T).

So with 1 k-ohm and 0.1 uF the time-constant is 1000 x 1E-7 or 100 microseconds, so the cutoff frequency is 10,000/2pi which is 1592 Hz.

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Related Questions

Frequency response of bjt amplifier?

All amplifier typically exhibit a band-pass frequency response. The cut off frequency in the low end is usually determined by the coupling band bypass capacitor .and the high frequency limit is typically determined by internal capacitances in the transistor itself.


What will happen if the signal frequency is greater than cut-off frequency in a waveguide?

If the signal frequency exceeds the cut-off frequency in a waveguide, the wave will not propagate through the waveguide and will be attenuated. This is because the waveguide is designed to support only certain modes of propagation, and frequencies above the cut-off do not satisfy the waveguide's mode conditions. Instead, the signal will either reflect back or be absorbed, leading to a loss of signal strength.


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What will be the change in frequency response curve of JFET if Ci and Ce are interchanged?

If the input capacitance (Ci) and the emitter bypass capacitance (Ce) are interchanged in a JFET circuit, the frequency response curve will be significantly affected. Ci typically influences the high-frequency response, while Ce primarily affects the low-frequency response by providing a bypass path for AC signals. Interchanging them may lead to a shift in the cutoff frequencies, potentially degrading the amplifier's performance and altering the gain at different frequencies. As a result, the overall frequency response curve could exhibit higher low-frequency roll-off and altered high-frequency behavior.


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