for three phase the calculation is 30,000 = 1.73*V*I - simple as that.
For single Phase the calculation is 30,000 = V*I - simple as that
It is important to note the voltage in the first line is Line to Line (typically how it is specified in three phase power systems), and the second line it is Line to neutral.
A 30KVA transformer is the same as 30,000VA to find out the Amps you need to divide the voltage if the transformer is single phase for example:
30,000VA / 480V = 62.5 Amps
The calculation for a 3 phase transformer is the VA / voltage / 1.73 for example:
30,000VA /480V / 1.73 = 36.12 Amps
The formula you are looking for is I = W/E. Amps = Watts/Volts.
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
You will need a 3:1 ratio transformer. An output current of 20 amps and a secondary voltage of 47 volts, results in a transformer rated at 940 VA.
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
It depends on the incoming primary voltage. For a 5kva utility transformer receiving 15,000 volts on the primary the current drawn would be one third of one amp to give you an output of 5,000 VA (watts). Just remember this, volts x amps = watts or volt amps.
2.083 amps
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
To calculate the amperage in the secondary side of a transformer, you can use the formula: Amps = kVA / (Volts x Sqrt(3)). For a 250 kVA transformer with a 220-volt secondary, the amperage will be approximately 660.4 Amps.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
That gives you 18.5 amps.
The formula you are looking for is I =W/E. Or Amps = Watts/Volts.
The number of amps a transformer can carry on its secondary side depends on its power rating (in watts or VA) and the voltage of the secondary winding. You can calculate the current (in amps) using the formula: Amps = Watts / Volts. For example, if you have a 1000 VA transformer with a 10V secondary, it can carry 100 amps (1000 VA / 10V = 100A). Always ensure the transformer is rated for the desired load to avoid overheating or damage.
160 amps at 12v.
160 amps at 12v.
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
480 volts is probably 3-phase (Line to line) voltage, so: 1500K / (480 x 1.732) = I = 1804Amps