When two 4-ohm resistors are connected in parallel across 12 volts:
-- Each resistor has 12V across it, so the current is I = E/R = 12/4 = 3 amperes.
-- The total current from the battery is 6 amperes.
-- The effective resistance as seen by the battery is R = E/I = 12/6 = 2 ohms.
-- If you didn't know the voltage of the battery, you would calculate the
effective resistance of the parallel resistors in advance like this:
1/R = 1/4 + 1/4 = 1/2
R = 2 ohms.
When you connected them to a battery, the battery would agree.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
Yes In parallel circuit , current entering into the circuit will be divided intodifferent paths ( resistances) . Amount of current flow depends upon the magnitude of resistance applied in the circuit. Total current after passing through the circuit will be the sum of all current through each resistance.
To find the current flowing through a 16 V battery with a resistance of 5.1 ohms, you can use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). Thus, I = V/R = 16 V / 5.1 ohms ≈ 3.14 A. Therefore, approximately 3.14 amperes of current flows through the circuit.
in a parallel circuit resistance decreases increasing the current.
If resistance in a circuit increases, the current flowing through the battery decreases according to Ohm's Law (I = V/R). This reduction in current can lead to lower power output and may cause the battery to operate less efficiently. Additionally, higher resistance can result in increased heat generation at the resistive element, potentially affecting the battery's performance and lifespan. In extreme cases, if the resistance is too high, the circuit may not function at all.
The net resistance of the circuit connected to the battery in Figure 1 is the total resistance that the current encounters when flowing through the circuit. It is calculated by adding up the individual resistances of all the components in the circuit.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
A circuit with five resistors and a battery is constructed by connecting the resistors in series or parallel to create a closed loop for the flow of electric current from the battery through the resistors. The battery provides the energy for the current to flow through the resistors, which resist the flow of current. The arrangement of the resistors and the battery determines the overall resistance and current flow in the circuit.
If at battery,parallel circuit shorts then equivalent resistance of circuit becomes approximately 0 Ohms,and therefore as current follows low resistance path infinite amount of current due to low resistance will flow through the wire so,entire parallel circuit will short out,but wire will burn and battery may get damaged. Name:Sumit Karnik.
If a 1.5 volt battery is replaced by a 9 volt battery in a circuit, the current flowing through the circuit will likely increase. This is because the higher voltage of the 9 volt battery will provide more electromotive force, pushing more current through the circuit, assuming the resistance remains the same.
This circuit is a series circuit, as the current flows sequentially through resistor 1, then through resistor 2, before returning to the battery. The same current passes through both resistors, and the total resistance is the sum of their individual resistances. The voltage across the circuit is divided between the two resistors according to their resistance values. Additionally, if one resistor fails, the entire circuit will be interrupted, stopping the current flow.
No, current does not flow through a circuit by taking the path of least resistance. Instead, current flows through all available paths in a circuit, with the amount of current in each path determined by the resistance of that path.
Resistance = (voltage across the circuit) divided by (current through the circuit) =12 / (3 x 10-3) = 4 KΩ
In a complex circuit with various elements (resistors, capacitors etc.) and one battery, the various circut elements contribute to draw a certain amount of current "I"from the battery at some terminal voltage "V". The "equivalent" resistance of the various circuit elements is that resistance "R" which will draw the same current , at the same terminal voltage, as the complex circuit. So to find "R" you simply imagine replacing the complex circuit with "R" by attaching "R" across the terminals of the battery and use Ohms law to find "R" , demanding "I" and "V" are the same. So then R = V/I.
A battery is rated to supply a certain number of volts. However, it actually supplies less, because they are "lost" as the current has to get out of the battery in the first place.(The battery has internal resistance)The amount of lost volts depends on the current being drawn:The less resistance a circuit has, the more current is drawn, because it's easier to flow.Example:If the circuit has little resistance, it draws a large current and the battery's internal resistance causes more lost volts.If the circuit has high resistance, it draws a small current and there are fewer lost volts.This is why when you short-circuit a battery (give it hardly any resistance to go through) it heats up and may explode. A large current is drawn and all the volts are used by the battery's internal resistance.
The relationship between resistance and current in an electrical circuit is described by Ohm's Law, which states that the current flowing through a circuit is directly proportional to the voltage applied and inversely proportional to the resistance in the circuit. In simpler terms, as resistance increases, the current flowing through the circuit decreases, and vice versa.
In an electrical circuit, the relationship between current and resistance is described by Ohm's Law. This law states that the current flowing through a circuit is directly proportional to the voltage applied and inversely proportional to the resistance in the circuit. In simpler terms, as resistance increases, the current flowing through the circuit decreases, and vice versa.