Use a linked-list.
Using if-else statement #include<stdio.h> #include<conio.h> int main(void) { long int n,i; clrscr(); printf("\n Enter any two nos."); scanf("%ld%ld",&n,&i); if(n>i) printf("\nThe largest no. is=%ld",n); else printf("\nthe largest no. is=%ld",i); getch(); return 0; } using ternary operator #include<stdio.h> #include<conio.h> int main(void) { int n,i,a; clrscr(); printf("\n Enter any two nos."); scanf("%d%d",&n,&i); a=(n>i?n:i); printf("\nThe largest no. is=%d",a); getch(); return 0; }
Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
10 cls 11 c = 0 20 for n =1 to 10 30 input"enter no.";a 40 c=c+a 50 next n 60 print c
// HI THIS IS MAYANK PATEL /*C Program to find Maximum of 3 nos. using Nested if*/ #include<stdio.h> #include<conio.h> void main() { int a,b,c; // clrscr(); printf("Enter three number\n\n"); scanf("d%d",&a,&b,&c); if(a>b) { if(a>c) { printf("\n a is maximum"); } else { printf("\n c is maximum"); } } else { if(b>c) { printf("\n b is maximum"); } else { printf("\n c is maximum"); } } getch(); }
if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;
How do you lose weight using super nos pump
just press enter
If both Windows and Unix are using TCP/IP as their primary NOS there isn't much difference to speak of.
Just now you could write "TODAY" but the answer would not be valid ever again.
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
#include<stdio.h> #include<conio.h> void main() { int a[5],i,j,t; clrscr(); printf("Enter 5 nos.\n\n"); for (i=0;i<5;i++) scanf("%d",&a[i]); for (i=0;i<5;i++) { for(j=i+1;j<5;j++) { if(a[i]>a[j]) { t=a[i]; a[i]=a[j]; a[j]=t; } } } printf("Ascending Order is:"); for(j=0;j<5;j++) printf("\n%d",a[j]); getch(); }
Miguel nos/se lo sirvio. ('Nos' - us. 'Se' - them)
Enter a private online game. Go to beach and use NOS until you have no more, and then drive into the water. Quick fix and repeat process. Or, enable NOS cheat. Drive into water with just the NOS, no gas and repeat process.
search long division online click on mathsonline org enter nos
* Nob.s * Nog.s * Nor * Nos * Not
Nos. Amp
Nos is short for Numbers.