The current in a circuit, expressed in milliamperes, is1,000 x (battery or power supply voltage)/(resistance connected between the power supply terminals)If you increase the voltage of the battery or power supply, the current in the circuitincreases proportionally, at least until something in the circuit gets hot, melts, fuses,and opens the circuit.
In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)
The equivalent resistance of multiple resistors connected in series is the sum of theindividual resistances.(10 + 60 + 50) = 120 ohms for this particular trio of resistors in series.It makes no difference what battery they may be connected to, or if they're connected toany power supply at all.
In simple way resistor bank contains number of resistors in series or parallel combination. They are connected in parallel to decrease the resistance and increase current rating and power dissipation.And they are connected in series to increase resistance and power dissipation.
There is internal resistance in a battery because a battery is not an ideal voltage source. It may be close, but it is not ideal. As a result, analytically, there will be some series resistance, resistance which places a limit on the maximum current that the battery can provide. While no battery is ideal, most are sufficiently ideal to not require any consideration of the internal resistance. If your circuit is dependent on the internal resistance of a battery, then it is probably not well suited for that application.
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Doesn't work like that. Current drain is dependent on the (internal resistance of the battery and the) resistance/power requirements of what's connected to the battery. If shorted out, the current - unless the battery is fused or otherwise protected - can go into tens of amps.
That will depend on the sum of the load resistance and the internal resistance of the battery (this is true for all power sources, not just 6 volt batteries). Small compact batteries tend to have higher internal resistance and therefore are more limited in the current they can deliver to a given load than larger batteries.
it determines how well the current flows through the wires. ANSWER: When there is no outside power connected to it. But some power is necessary to read the resistance so the meter battery will supply the current necessary to measure the IR drop and translate that to resistance
If Rin = Rout, then the voltage at the output of the device goes down to half of the value that the circuit has without the external resistance. Scroll down to related links and look at "Interconnection of two audio units".
I believe it causes full power of battery flow to the neg. Where used photons of energy should be. Perhaps it gets hot enough then leaks?
It will turn off. Because "sleeping" still takes power from the battery, unless the laptop is connected to the power source.
If two identical batteries were connected in series, the resulting voltage would double, the available current would remain the same, and the available power would double. Note that, by Ohm's Law and the Power Law, doubling the voltage into a set resistance would double the current and quadruple the power. This is inconsistent with the battery's ability to provide a certain current, so you would also need to double the load resistance, otherwise you could damage the battery.
The current in a circuit, expressed in milliamperes, is1,000 x (battery or power supply voltage)/(resistance connected between the power supply terminals)If you increase the voltage of the battery or power supply, the current in the circuitincreases proportionally, at least until something in the circuit gets hot, melts, fuses,and opens the circuit.
if the resistance is decreased and the current stays the same, then the power decreases.
The vehicle would run on battery power until the battery runs out of power.
If three equal resistors are connected in parallel, the equivalent resistance will be one-third of the resistance in series. This lower resistance will result in a higher current flowing through the resistors when connected in parallel compared to when they are in series. Therefore, the power dissipated by the resistors in parallel will be greater than 10W.