In a series circuit, the current remains the same through all components, as there is only one path for the current to flow. In contrast, in a parallel circuit, the total current is divided among the multiple paths, meaning that each branch can have different currents depending on their resistance. Overall, the total current in a parallel circuit is the sum of the currents through each branch.
Overall brightness (not individual bulbs' brightness) will increase when we connect them in parallel & it will decrease when we connect them in series.
If three identical bulbs are connected in parallel to a battery, all three bulbs would have equal brightness.Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that, in a parallel circuit, the voltage across each parallel element is the same.There are effectively 6 series circuits in this example - battery and A - battery and B - battery and C - A and B - A and C - and B and C. These six combinations are also parallel circuits, and they are also in parallel with each other.
They can be connected to either supply. A bulb in series that fails, will cause all the other bulbs to go out. A bulb in parallel that fails, will have no adverse effect on the other bulbs in that circuit
As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
Efficiency isn't the question. They just do different things. For example, if you look at a typical lighting circuit in a house, all the bulbs on a circuit are in parallel. They each have the same voltage across the bulbs. If you rewired this so that the bulbs were in series then the voltage would be divided across each bulb and if one bulb burned out the others in series would get no current and would not light. If you had two 60Watt bulbs in parallel in your house, each would draw 1/2 Amp. Add another bulb and it would draw 1/2 amp as well, for a total of three 60W bulbs drawing 1.5 amps from the power source. If the same three bulbs were in series there would be 40 Volts across each one with a current of 1/6 amps per bulb. Hence each bulb would be about 1/3 as bright as in the parallel circuit.
As the number of bulbs in a series circuit increases, the current decreases. As the number of bulbs in a parallel circuit increases, the current increases.
A: If put in series current will decrease if put in parallel current will increase assuming the input voltage remains the same
When more bulbs are added to a parallel circuit, the total current in the circuit increases because each bulb provides an additional path for current to flow. This is because in a parallel circuit, the current is divided amongst the branches, so adding more branches (bulbs) will increase the total current.
If you add more cells in series with the bulbs, the current will increase as the voltage across the bulbs increases. If you add more cells in parallel with the bulbs, the current will stay the same because the voltage of the cells does not increase when they are added in parallel.
current in series always stays the same
Voltage remains constant; current increases.
If the bulbs are connected in series, the same current passes through each bulb. However, if the bulbs are connected in parallel, the current will split between the bulbs with the lower resistance receiving more current.
The total current provided by the battery increases as more bulbs are added to a parallel circuit. This is because each branch in a parallel circuit receives the full voltage of the battery, leading to more current flowing through each branch as more loads (bulbs) are added.
Brighter in parallel. In series the voltage is divided between the two bulbs, thus the current will only be half so that the power of each bulb will only be one quarter (of 5 watts) in the series set-up.
parallel
Bulbs in a parallel circuit draw the same amount of current, so each will display the same brightness. Bulbs in a series circuit share the current so all bulbs will appear dimmer.
They dim as the total resistance of series of resistances is the sum of the resistances; and current = V/R.