That depends on the programming language and the exact implementation of max. Normally, a max function returns the largest of two variables of the same type but can also be applied to a sequence container with 2 or more elements. Both versions may also include a user-defined predicate to perform the comparison(s).
In the C++ standard library, it is implemented as a generic algorithm (a function template) with 4 overloads. These functions become accessible when you include the <algorithm> header from the standard library. They each have the following definitions:
// TEMPLATE FUNCTION max
template<class _Ty> inline
_Post_equal_to_(_Left < _Right ? _Right : _Left)
const _Ty& (max)(const _Ty& _Left, const _Ty& _Right)
{ // return larger of _Left and _Right
return (_DEBUG_LT(_Left, _Right) ? _Right : _Left);
}
template<class _Ty> inline
_Ty (max)(_XSTD initializer_list<_Ty> _Ilist)
{ // return leftmost/largest
const _Ty *_Res = _STD max_element(_Ilist.begin(), _Ilist.end());
return (*_Res);
}
// TEMPLATE FUNCTION max WITH PRED
template<class _Ty,
class _Pr> inline
const _Ty& (max)(const _Ty& _Left, const _Ty& _Right, _Pr _Pred)
{ // return larger of _Left and _Right using _Pred
return (_DEBUG_LT_PRED(_Pred, _Left, _Right) ? _Right : _Left);
}
template<class _Ty,
class _Pr> inline
_Ty (max)(_XSTD initializer_list<_Ty> _Ilist, _Pr _Pred)
{ // return leftmost/largest
const _Ty *_Res = _STD max_element(_Ilist.begin(), _Ilist.end(), _Pred);
return (*_Res);
}
In Java, assuming you already created an array of int's, called myArray:int max = myArray[0];int sum = 0;for (int i = 0; i < myArray.length; i++){sum += myArray[i];if (myArray[i] > max)sum = myArray[i]}
public int max(int x, int y, int z){ return Math.max(x,Math.max(y,z)); } The method Math.max() only accepts 2 arguments, so you need to perform this method twice if you want to compare 3 numbers, as per the code above.
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** pseudo code ** if array length == 1, return first element else if array length > 1 max = first element for second item to last item if item > max max = item return max else // array length is 0 error
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did max planck follow the scientific method
In Java, assuming you already created an array of int's, called myArray:int max = myArray[0];int sum = 0;for (int i = 0; i < myArray.length; i++){sum += myArray[i];if (myArray[i] > max)sum = myArray[i]}
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