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Because Reverse bias constrained the majority carries to repel from both side (P side & N side)hence Depletion layer is formed with a large extant of majority carriers hence the depletion region is wider in reverse bias.

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How can breakdown voltage of a diode be controlled?

The breakdown voltage of a diode can be controlled by altering its doping concentration and the thickness of the depletion region. Increasing doping levels generally leads to a lower breakdown voltage, while a wider depletion region can increase it. Additionally, the diode's material properties and structural design, such as using different semiconductor materials or introducing guard rings, can also influence the breakdown voltage. By carefully engineering these factors, manufacturers can create diodes with specific breakdown voltage characteristics to suit various applications.


What happens in the depletion region in reverse bias?

in forward biasing depletion region width decreases and in reverse biasing it increases .


Why charge carriers are not present in depletion region of am pn junction?

depletion region is formed only after recombination of holes and electrons..so in depletion region there are only and only immoble positive and nagative ions...hence,there is no charge carrier..


What will be the result on increase of applied voltage but below the depletion barrier in a reverse biased diode?

When the applied voltage is increased in a reverse-biased diode but remains below the depletion barrier, the width of the depletion region will increase, leading to a higher electric field across the junction. This results in a minimal increase in the reverse current, primarily due to the thermal generation of minority carriers. However, the diode will not conduct significantly until the breakdown voltage is reached, at which point a rapid increase in current occurs.


What is the effect on threshold voltage of a mos capacitor on increasing substrate doping concentration?

The threshold voltage will be increased (in case of an N-Mos), because the charge in the depletion region formed under the channel will be more (high density) and hence gate voltage has to overcome this charge for strong inversion. Vt = (work function difference of gate and substrate) + 2*(substrate Fermi voltage) + (Qd/Cox) Where, Qd = charge in Depletion region in Coulomb Cox = Oxide capacitance

Related Questions

What is the effect of doping on depletion region?

increases with doping


How can breakdown voltage of a diode be controlled?

The breakdown voltage of a diode can be controlled by altering its doping concentration and the thickness of the depletion region. Increasing doping levels generally leads to a lower breakdown voltage, while a wider depletion region can increase it. Additionally, the diode's material properties and structural design, such as using different semiconductor materials or introducing guard rings, can also influence the breakdown voltage. By carefully engineering these factors, manufacturers can create diodes with specific breakdown voltage characteristics to suit various applications.


Why depletion layer width at the collector junction are more than the depletion layer width at the emitter junction?

The depletion layer width at the collector junction is typically wider than that at the emitter junction due to the differences in doping concentrations. The collector region is generally lightly doped compared to the heavily doped emitter region, resulting in a larger electric field and a broader depletion region. Additionally, the collector junction must accommodate a higher reverse bias, which further expands the depletion region to maintain charge neutrality and facilitate efficient charge separation.


Why base spreading resistance is not considered at low frequencies?

Base spreading resistance depends on doping of the p-n junction and also the width of depletion region of the p-n junction. Thats what i knw.


What is significance of depletion region?

Depletion region is the region where current carriers such as electrons and holes are absent.


What will happen to the depletion region when the P-N junction is supplied by forward bias?

depletion region will decrease.


What happens in the depletion region in reverse bias?

in forward biasing depletion region width decreases and in reverse biasing it increases .


Why depletion region is small in germanium compared to silicon?

The depletion region is smaller in germanium compared to silicon because germanium has a lower bandgap energy, meaning that charge carriers can easily cross the depletion region and recombine on the other side. This results in a smaller built-in potential and a smaller depletion region in germanium.


How depletion region?

depletion region formed by either side of p&n junctions mobile charges accumulate in that places.Type your answer here...


Why charge carriers are not present in depletion region of am pn junction?

depletion region is formed only after recombination of holes and electrons..so in depletion region there are only and only immoble positive and nagative ions...hence,there is no charge carrier..


Is a depletion region a good conductor?

No, a depletion region is not a good conductor. It is an insulating region formed in a semiconductor material when a voltage is applied, creating a barrier to the flow of current.


Does the atmosphere prevent depletion of the ozone over Antarctica?

The atmosphere does not protect the ozone depletion. It is the region where the ozone depletion occurs.