Because Reverse bias constrained the majority carries to repel from both side (P side & N side)hence Depletion layer is formed with a large extant of majority carriers hence the depletion region is wider in reverse bias.
The breakdown voltage of a diode can be controlled by altering its doping concentration and the thickness of the depletion region. Increasing doping levels generally leads to a lower breakdown voltage, while a wider depletion region can increase it. Additionally, the diode's material properties and structural design, such as using different semiconductor materials or introducing guard rings, can also influence the breakdown voltage. By carefully engineering these factors, manufacturers can create diodes with specific breakdown voltage characteristics to suit various applications.
in forward biasing depletion region width decreases and in reverse biasing it increases .
depletion region is formed only after recombination of holes and electrons..so in depletion region there are only and only immoble positive and nagative ions...hence,there is no charge carrier..
When the applied voltage is increased in a reverse-biased diode but remains below the depletion barrier, the width of the depletion region will increase, leading to a higher electric field across the junction. This results in a minimal increase in the reverse current, primarily due to the thermal generation of minority carriers. However, the diode will not conduct significantly until the breakdown voltage is reached, at which point a rapid increase in current occurs.
The threshold voltage will be increased (in case of an N-Mos), because the charge in the depletion region formed under the channel will be more (high density) and hence gate voltage has to overcome this charge for strong inversion. Vt = (work function difference of gate and substrate) + 2*(substrate Fermi voltage) + (Qd/Cox) Where, Qd = charge in Depletion region in Coulomb Cox = Oxide capacitance
increases with doping
The breakdown voltage of a diode can be controlled by altering its doping concentration and the thickness of the depletion region. Increasing doping levels generally leads to a lower breakdown voltage, while a wider depletion region can increase it. Additionally, the diode's material properties and structural design, such as using different semiconductor materials or introducing guard rings, can also influence the breakdown voltage. By carefully engineering these factors, manufacturers can create diodes with specific breakdown voltage characteristics to suit various applications.
The depletion layer width at the collector junction is typically wider than that at the emitter junction due to the differences in doping concentrations. The collector region is generally lightly doped compared to the heavily doped emitter region, resulting in a larger electric field and a broader depletion region. Additionally, the collector junction must accommodate a higher reverse bias, which further expands the depletion region to maintain charge neutrality and facilitate efficient charge separation.
Base spreading resistance depends on doping of the p-n junction and also the width of depletion region of the p-n junction. Thats what i knw.
Depletion region is the region where current carriers such as electrons and holes are absent.
depletion region will decrease.
in forward biasing depletion region width decreases and in reverse biasing it increases .
The depletion region is smaller in germanium compared to silicon because germanium has a lower bandgap energy, meaning that charge carriers can easily cross the depletion region and recombine on the other side. This results in a smaller built-in potential and a smaller depletion region in germanium.
depletion region formed by either side of p&n junctions mobile charges accumulate in that places.Type your answer here...
depletion region is formed only after recombination of holes and electrons..so in depletion region there are only and only immoble positive and nagative ions...hence,there is no charge carrier..
No, a depletion region is not a good conductor. It is an insulating region formed in a semiconductor material when a voltage is applied, creating a barrier to the flow of current.
The atmosphere does not protect the ozone depletion. It is the region where the ozone depletion occurs.