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Energy of photon in joules = Planck's Constant (in Joule seconds) * greek letter Nu for frequency (units of 1/seconds)

Planck's Constant = 6.626 * 10^-34 Joule seconds

You can type "Planck's constant" into Google to calculate this (this is what I did).

(Planck's constant * 4 * (10^7)) / s = 2.6504272 × 10-26 joules

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14y ago

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What is the approximate energy of a photon having a frequency of 4 107 hz?

The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 4 x 10^7 Hz is approximately 2.65 x 10^-26 Joules.


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The energy of a photon can be calculated using the equation E = hf, where E is energy, h is Planck's constant (6.626 x 10^-34 J*s), and f is frequency. Rearranging the equation, you can find that the frequency (f) of a photon with energy 5 x 10^-24 J is approximately 7.54 x 10^9 Hz.


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