INCREASES
Voltage is not measured in ohms. It is measured in volts.
Ohms, resistance in an inductor increases as the frequency of the AC signal increases, this "artificial resistance" is called impedence, and it is measured in ohms
According to ohms law... V=I * R So from the given values V = 4.3*16 = 68.8 Volts
Ohms measure electrical resistance. The resistance in ohms is the voltage divided by the current.
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
The question cannot be answered without more information, such as the current or power.
V=I*R -- Potential (Voltage, V) = Current (Amperage, I) * Resistance (Ohms)2A*5Ohms = 10V
If the voltage is fixed, the using Ohms law: V=IxR If R increases, then the current will decrease proportionally.
NONE! By itself this is a meaningless question. Doubt it? pick up a 3 ohm resister and see if you get anything in amperage out of it . add some voltage to it and you will get some amperage, depending on the amount of voltage. Of course add to much voltage and you will burn the resistor up, depending on its wattage rating
Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.
I=v/r =110/121 =0.909A
Here is the formula you use. I = E/R. I = amperage, E = volts, R = resistance in ohms.
Current is common throughout the world. The current is based on what the load draws. The equation you are looking for is Amps = Watts/Volts. Other equations for amperage are Amps = Sq root of Watts/Ohms and Amps = Volts/Ohms. So as you can see the amperage is dependant upon the the value of voltage, wattage and resistance.
I=e/r
according to ohms law V=IR where V=voltage I=current R= resistance so simply we can say that as I decreases R has to increase to maintain V.