For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel. CO2= 44.0 grams
1.50 moles CO2 × (44.0 grams) = 66.0 grams CO2
To find the number of moles in 6.5 grams of CO2, you first need to calculate the molar mass of CO2, which is 44.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 6.5 grams / 44.01 g/mol = 0.148 moles of CO2.
To find the total mass of 12 moles of CO2, you would multiply the molar mass of CO2 (44 g/mol) by the number of moles (12 moles). This gives: 44 g/mol x 12 mol = 528 grams. Therefore, the total mass of 12 moles of CO2 would be 528 grams.
To find the mass of 2.0 moles of carbon dioxide (CO2), first determine the molar mass of CO2. The molar mass is calculated as follows: carbon (C) has a mass of about 12.01 g/mol and oxygen (O) has a mass of about 16.00 g/mol. Therefore, CO2 has a molar mass of approximately 44.01 g/mol (12.01 + 2 × 16.00). Multiplying the molar mass by the number of moles: 2.0 mol × 44.01 g/mol = 88.02 g. Thus, the mass of 2.0 moles of CO2 is approximately 88.02 grams.
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
To find the number of moles in 6.5 grams of CO2, you first need to calculate the molar mass of CO2, which is 44.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 6.5 grams / 44.01 g/mol = 0.148 moles of CO2.
To calculate the grams of CO2 in 14 mol of the compound, first find the molar mass of CO2: 1 carbon atom (12.01 g/mol) + 2 oxygen atoms (16.00 g/mol each) = 44.01 g/mol. Next, multiply the molar mass of CO2 by the number of moles given (14 mol): 44.01 g/mol x 14 mol = 616.14 grams of CO2.
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
To find the total mass of 12 moles of CO2, you would multiply the molar mass of CO2 (44 g/mol) by the number of moles (12 moles). This gives: 44 g/mol x 12 mol = 528 grams. Therefore, the total mass of 12 moles of CO2 would be 528 grams.
To find the number of molecules in 33.6g of CO2, you first need to convert grams to moles. The molar mass of CO2 is 44 g/mol. Therefore, 33.6g is equal to 33.6g / 44 g/mol = 0.764 moles of CO2. Using Avogadro's number (6.022 x 10^23 molecules/mol), you can calculate that 0.764 moles of CO2 is equal to 0.764 mol x 6.022 x 10^23 molecules/mol = 4.6 x 10^23 molecules of CO2.
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
The molar mass of LiOH is 23.95 g/mol for lithium, 15.999 g/mol for oxygen, and 1.008 g/mol for hydrogen, totaling 41.943 g/mol for LiOH. This means that for every 41.943 grams of LiOH, 44.01 grams of CO2 can be absorbed. To find out how much CO2 can be absorbed by 580.0 grams of LiOH, you can set up a simple ratio and cross-multiply to get your answer.
To find the mass in grams of 0.330 mol of calcium, you need to multiply the number of moles by the molar mass of calcium. The molar mass of calcium is approximately 40.08 grams/mol. So, 0.330 mol * 40.08 g/mol = 13.23 grams of calcium.
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams454 grams CO2 / (44.0 grams) = 10.3 moles CO2
In the process of photosynthesis, the overall reaction involves 6 molecules of CO2 producing 1 molecule of glucose. The molar mass of CO2 is 44 g/mol and the molar mass of glucose is 180 g/mol. To produce 180 grams of glucose, you would need 6 * 44 = 264 grams of CO2.
Using the molar mass of CaCO3 (100.09 g/mol), we find that 25g is equal to 0.249 mol. According to the balanced equation, 1 mol of CaCO3 produces 1 mol of CO2, so 0.249 mol of CaCO3 will produce 0.249 mol of CO2. Finally, using the molar mass of CO2 (44.01 g/mol), we determine that 0.249 mol of CO2 corresponds to 10.95 g.