What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
To prepare a 1 mM solution of salicylic acid, first calculate the mass required using the formula: mass (g) = molarity (mol/L) × volume (L) × molar mass (g/mol). The molar mass of salicylic acid is approximately 138.12 g/mol. For 1 liter of a 1 mM solution, you would need 0.1381 g of salicylic acid. Dissolve this mass in distilled water and then dilute to a total volume of 1 liter.
To prepare a 1 mole solution of dimethoxyhydroxyacetophenone, you would dissolve 166.21 grams of the compound in enough solvent to make a total volume of 1 liter. Calculate the required weight based on the molar mass of dimethoxyhydroxyacetophenone (C10H12O4).
They're actually exactly the same in that neither of them exists.
To calculate the molar mass of TiCl4, first find the molar mass of each element: Ti (Titanium) has a molar mass of 47.87 g/mol, and Cl (Chlorine) has a molar mass of 35.45 g/mol. Next, multiply the molar mass of each element by the number of atoms in the compound: Ti(Cl)4 = 47.87 + 4(35.45) = 47.87 + 141.8 = 189.67 g/mol. Therefore, the molar mass of TiCl4 is 189.67 g/mol.
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
To prepare a 1 molar (1 M) solution of a substance, you need to know its molar mass. The molar mass of acetic acid (CH₃COOH) is approximately 60.05 g/mol. Therefore, to make 1 liter of a 1 M solution, you would need 60.05 grams of acetic acid. If you meant a different substance by "ACLU," please specify for an accurate calculation.
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
To make a 1 molar solution of sodium azide, you would need to dissolve 65.01 g of sodium azide in water to make 1 liter of solution. Since you have 98 mg of sodium azide, you would need to add enough water to make a final volume of 1 liter to create the 1 molar solution.
Find out the molecular weight of LactoseAdd that many grams of Lactose into a 1000ml volumetric flaskMake up the volume to 1000ml with waterYour 1 Molar solution of Lactose is ready---------------The molar mass of lactose is 342,3 g/mol; the solubility of lactose is 216 g/L at20 0C. Consequently you cannot prepare a molar solution of lactose.
To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.
To make a 0.1 molar solution from a 1.0 molar solution, you would dilute the original solution by a factor of 10. For example, you could mix 1 part of the 1.0 molar solution with 9 parts of solvent (like water) to achieve a final concentration of 0.1 molar.
1 molar solution of sugar water contains 342,3 g sucrose.
You have to dissolve 1.00 mol, that is 98.15 g CH3COOK (its molar mass being 98.15 g/mol), in upto 1.000 L.(Suggested procedure: dissolve 98.15 g CH3COOK in not more then 900 mL, homogenize and fill up to exactly 1.000 L by carefully adding the last millilitres water).