0
What else can I help you with?
Calculate the molar solubility of lead thiocyanate in 0.500?
To calculate the molar solubility of lead thiocyanate in 0.500 L of water, you need to know the Ksp value for lead thiocyanate. Can you provide that information?
What is the molar solubility of silver oxalate Ksp for Ag2 C2 O4 is 5.4x10 12?
The molar solubility of silver oxalate can be calculated using the given Ksp value. First, calculate the solubility product (Ksp) by taking the square root of the given value, which is √(5.4x10^12) ≈ 2.3x10^6. This means the molar solubility of silver oxalate is approximately 2.3x10^-6 mol/L.
What is the mass percent of calcium in calcium suppleiment if 1.15g of CaCO3 is extracted from a 2.70g pill?
1.15 (g CaCO3) / 100.1 (g/mol CaCO3) =1.149*10-2 (mol Ca)1.149*10-2 (mol Ca) = 1.149*10-2 (mol Ca) * 40.08 (g/mol Ca) = 0.4604 g Ca0.4604 g Ca = 0.4604 g Ca / 2.70 g Supplement = 0.1705 * 100% = 17.1% Calcium (m%)
How do you convert alkalinity as HCO3 to CaCO3?
To convert alkalinity (HCO3) to CaCO3, you need to use the molar mass ratio. For every mole of bicarbonate (HCO3), you have one mole of carbonate (CO3) in CaCO3. So, to convert, you can multiply the HCO3 concentration by a factor of 50.04 (molar mass of CaCO3/molar mass of HCO3).
How do you determine the number of atoms in CaCO3?
To determine the number of atoms in CaCO3, you would first calculate the molar mass of CaCO3 (40.08 g/mol + 12.01 g/mol + 3(16.00 g/mol)). Then, you would divide the given mass of CaCO3 by the molar mass to find the number of moles. Finally, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to the number of atoms in CaCO3.
Calculate the molar solubility of lead thiocyanate in 0.500?
To calculate the molar solubility of lead thiocyanate in 0.500 L of water, you need to know the Ksp value for lead thiocyanate. Can you provide that information?
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of CaCO3 is 73.4kg?
To find the number of moles in 73.4 kg of CaCO3, we first need to calculate the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. Converting 73.4 kg to grams gives 73,400 g. Dividing 73,400 g by the molar mass of CaCO3 gives approximately 733 moles.
What is the mass of CaCO3?
Molar mass of CaCO3 = 100.0869 g/mol
What does the molar mass of C7H16 and the molar mass of CaCO3 have the same number of?
Both C7H16 and CaCO3 have a molar mass of approximately 116 grams per mole.
What is the molar solubility of silver oxalate Ksp for Ag2 C2 O4 is 5.4x10 12?
The molar solubility of silver oxalate can be calculated using the given Ksp value. First, calculate the solubility product (Ksp) by taking the square root of the given value, which is √(5.4x10^12) ≈ 2.3x10^6. This means the molar solubility of silver oxalate is approximately 2.3x10^-6 mol/L.
The molar mass of CaCO3 is greater than the molar mass of CaNO32?
No, this statement is incorrect. The molar mass of CaCO3 (calcium carbonate) is 100.09 g/mol, while the molar mass of Ca(NO3)2 (calcium nitrate) is 164.08 g/mol. Therefore, the molar mass of Ca(NO3)2 is greater than that of CaCO3.
How do I calculate the molar solubility of copperII sulfide in 25M of CuCl2?
To calculate the molar solubility of copper(II) sulfide, you need to consider the solubility product constant (Ksp) of CuS. Once you have the Ksp value, set up an equilibrium expression for the dissociation of CuS into Cu^2+ and S^2- ions. Use the initial concentration of CuCl2 to determine the concentration of Cu^2+ ions and then solve for the molar solubility of CuS.
What is the mass percent of calcium in calcium suppleiment if 1.15g of CaCO3 is extracted from a 2.70g pill?
1.15 (g CaCO3) / 100.1 (g/mol CaCO3) =1.149*10-2 (mol Ca)1.149*10-2 (mol Ca) = 1.149*10-2 (mol Ca) * 40.08 (g/mol Ca) = 0.4604 g Ca0.4604 g Ca = 0.4604 g Ca / 2.70 g Supplement = 0.1705 * 100% = 17.1% Calcium (m%)
How many grams of CaCO3 form if 155g of water reacts?
To determine the amount of CaCO3 formed, we need to know the molar ratio of water to CaCO3 in the chemical reaction. Without this information, it is not possible to calculate the amount of CaCO3 formed when 155g of water reacts.
How do you convert alkalinity as HCO3 to CaCO3?
To convert alkalinity (HCO3) to CaCO3, you need to use the molar mass ratio. For every mole of bicarbonate (HCO3), you have one mole of carbonate (CO3) in CaCO3. So, to convert, you can multiply the HCO3 concentration by a factor of 50.04 (molar mass of CaCO3/molar mass of HCO3).
How do you determine the number of atoms in CaCO3?
To determine the number of atoms in CaCO3, you would first calculate the molar mass of CaCO3 (40.08 g/mol + 12.01 g/mol + 3(16.00 g/mol)). Then, you would divide the given mass of CaCO3 by the molar mass to find the number of moles. Finally, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to the number of atoms in CaCO3.
