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Let x = hydrogen gas

532 / 2 = x / 3 .... x = 798L

Let y = nitrogen gas

532 / 2 = y / 1 .... y = 266L

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Why pure nitrogen and pure hydrogen are used in haber's process?

Pure nitrogen and pure hydrogen are used in Haber's process because they are the starting materials needed to produce ammonia. Nitrogen is the main component in the atmosphere, and hydrogen is readily available through various industrial processes. By using pure nitrogen and pure hydrogen, the reaction conditions can be controlled to optimize the production of ammonia.


Does a decomposing human produce ammonia gas?

No, but the bacteria and fungi doing the decomposition produce many gases including ammonia, carbon dioxide, hydrogen sulfide, and many worse smelling ones.A small portion ammonia, but most does not. Ammonia is a compound composed of nitrogen and hydrogen. When your body decomposes, much of the mass becomes carbon dioxide and water. Some if it goes into more complex compounds found in the organisms doing the decomposing.


How many moles of hydrogen must react to produce 68 grams of ammonia?

To calculate the moles of hydrogen needed to produce 68 grams of ammonia (NH₃), we start with the balanced chemical equation for the synthesis of ammonia: N₂ + 3H₂ → 2NH₃. The molar mass of ammonia is approximately 17 g/mol, so 68 grams of NH₃ corresponds to 68 g / 17 g/mol = 4 moles of NH₃. Since 3 moles of hydrogen are required for every 2 moles of ammonia, the moles of hydrogen needed is (4 moles NH₃) × (3 moles H₂ / 2 moles NH₃) = 6 moles of H₂. Therefore, 6 moles of hydrogen must react to produce 68 grams of ammonia.


How many liters of n2 gas at stp will be used to produce 8.16 liters of nh3 gas at stp are consumed?

Assuming that you mean the reaction of nitrogen and hydrogen to form ammonia N2 + 3H2 -> 2NH3 1 mole of nitrogen forms 2 moles of ammonia- so 4.08 l of nitrogen will be consumed to form 8.16 moles of ammonia. This assumes both are pretty ideal gases which is a reasonabale approximation.


What does NH3 form?

NH3 (ammonia) can form when nitrogen gas (N2) reacts with hydrogen gas (H2) in the presence of a catalyst, such as iron. The reaction is commonly known as the Haber process and is used to produce ammonia on an industrial scale. Ammonia is a colorless gas with a pungent odor and is commonly used in fertilizers, cleaning products, and as a refrigerant.

Related Questions

How many moles of hydrogen are required to produce 18.00 moles of ammonia?

N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3


How many moles of nitrogen are required to react with 3.4 moles of hydrogen to form ammonia feterlizer?

To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.


Nitrogen from the air can react with what element to make ammonia for fertilizer?

Hydrogen. Nitrogen from the air can react with hydrogen to produce ammonia for fertilizer in the Haber-Bosch process.


What mass of nitrogen and hydrogen needed to produce 91.3 Kg of ammonia?

Ammonia-NH3 2N+3H2=2NH3 2moles of Nitrogen produced 2moles of Ammonia (2*14)g of Nitrogen produced (2*17)g of Ammonia 28g of Nitrogen produced 34g of Ammonia 34g of Ammonia is produced by 28g of Nitrogen 0.034kg of Ammonia is produced by 0.028kg of Nitrogen 91.3kg of Ammonia will be produced by 0.028*91.3/0.034 91.3kg of Ammonia will be produced by 75.19kg of Nitrogen FOR HYDROGEN: 3moles of H2 produces 2moles of NH3 (2*3)g H2 produces 2*17g NH3 6g hydrogen produces 34g ammonia 0.006kg hydrogen produces o.o34kg ammonia 91.3kg ammonia will be produced by 91.3*0.006/.034=16.11kg of Hydogen Therefore, 75.19kg of Nitrogen and 16.11kg of Hydrogen will produce 91.3kg of Ammonia


How many moles of ammonia are produced from 12.0 moles of hydrogen?

N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.


How many moles of nitrogen are required to produce 18 mol of ammonia?

Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.


Ammonia gas NH3 can be manufactured by combining hydrogen and nitrogen gases If 28 g of nitrogen and 7 g of hydrogen are available how many grams of ammonia can be produced?

The balanced chemical equation for the formation of ammonia from nitrogen and hydrogen is N2 + 3H2 → 2NH3. From the equation, it can be seen that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Calculate the moles of nitrogen and hydrogen provided, determine the limiting reactant, and then use stoichiometry to find the grams of ammonia that can be produced.


What two elements produce NH3?

Ammonia (NH3) is composed from nitrogen (N) and hydrogen (H).


What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia?

10l nh3


One nitrogen molecule reacts with three hydrogen molecules to produce two ammonia molecules each containing one nitrogen and three hydrogen atoms?

The balanced equation for this reaction is: N2 + 3H2 -> 2NH3. During the reaction, one nitrogen molecule (N2) reacts with three hydrogen molecules (H2) to produce two ammonia molecules (NH3), each containing one nitrogen and three hydrogen atoms.


How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?

The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2


How many hydrogen molecules are needed to produce 525 grams of ammonia?

To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.