A molecule of glucose contains 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms. Their atomic masses are 12, 1 and 16 respectively. Therefore the Atomic Mass of glucose is 6x12+12x1+6x16=180 grams per mole.
It is a molecular species with the formula C6H12O6
C6H12O6. 6 atoms of carbon, 12 atoms of hydrogen, 6 atoms of oxygen.
Well first you should determine the molecular mass of your glucose molecule, then you should divide the molecular mass of all the carbon by this, if I recall correctly. Should look something like (12X6) / ((6X12)+(12X1)+(6X16)) All multiplied by 100 to make it a percentage. Gives something like 40% which sounds like the right answer looking at the question.
The molar mass of glucose is 180,16 g.
The molecular mass of cytosine is approximately 111.1 grams per mole.
The gram molecular mass of glucose is 180 gram. Reason. The atomicity of glucose is 24.
Glucose is a molecular compound, not ionic. It consists of covalent bonds between its carbon, hydrogen, and oxygen atoms.
It is a molecular species with the formula C6H12O6
the definition of 'empirical mass' is the simplest ratio of the molecular mass.for example: glucose.the molecular mass of glucose is C6 H12 O6 = 180but the empirical mass of glucose is C H2 O = 30hope this helps. it's all about ratios.
C6H12O6 is the molecular formula for sugar (glucose).Molecular mass/ molecular weight = (Number of C atoms) (Atomic weight of C) +(Number of H atoms) (Atomic weight of H) +(Number of O atoms) (Atomic weight of O) = (6) (12) + 12 (1) + 6 (16) = 180 (g/mole)
C6H12O6. 6 atoms of carbon, 12 atoms of hydrogen, 6 atoms of oxygen.
Wate is molecular , H2O. NaCl is giant ionic laattice and is not molecular when normally encountered. In terms of mass the formula unit of NaCl is greater than than the molecular mass of water.
The molecular weight of glucose is approximately 180.16 daltons.
I assume you mean the molecular mass. Its molecular mass is 86.175
I assume you mean the molecular mass. Its molecular mass is 342.3g/mol
Well first you should determine the molecular mass of your glucose molecule, then you should divide the molecular mass of all the carbon by this, if I recall correctly. Should look something like (12X6) / ((6X12)+(12X1)+(6X16)) All multiplied by 100 to make it a percentage. Gives something like 40% which sounds like the right answer looking at the question.
C6h12o6