In 'mgbr2' there are NO elements.
If you mean ' MgBr2'.
Then the elements are ;-
Magnesium (Mg)
Bromine (Br)
NB When writing chemical formulae, be it one or two letter symbol, the first letter is ALWAYS a CAPITAL letter. Hence my 'NO' for lower case letters.
MgBr2 is magnesium bromide. It is a combination of one cation ( atom) of magnesium and two anions( atoms of bromine.
The chemical formula of magnesium dibromide is MgBr2.
The reaction between Mg and Br2 results in the formation of MgBr2. The balanced chemical equation is: Mg + Br2 → MgBr2
MgBr2 is an ionic compound (salt: magnesium bromide)
Using a copy of the Periodic Table, showing the Atomic Masses. MgBr2 1 x Mg = 1 x 24 = 24 2 x Br = 2 x 80 = 160 24 + 160 = 184 the Mr ( Relative Molecular Mass) of tne molecule of MgBr2 Using the equation. moles = mass(g) / Mr Then mass(g = moles X Mt So for '7' moles mass(g) = 7 x 184 = 1288 g = 1.288 kg ( kilograms).
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
Magnesium (Mg) and Bromine (Br) - Magnesium Bromide - MgBr2
Magnesium bromide
The chemical formula of magnesium dibromide is MgBr2.
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
The reaction between Mg and Br2 results in the formation of MgBr2. The balanced chemical equation is: Mg + Br2 → MgBr2
MgBr2 is an ionic compound (salt: magnesium bromide)
MgBr2 is soluble in water and other polar solvents.
Yes.The cation,Mg 2+bonds with the anions,2Br 2-to form,MgBr2------------------magnesium bromide
There are 1.35 moles of MgBr2 in 1 L of solution, which corresponds to 2 moles of bromide ions. Therefore, in 750.0 mL of 1.35 M MgBr2 solution, there will be 1.0125 moles of bromide ions.
When magnesium and bromine combine, they form magnesium bromide, a white crystalline solid. This compound is composed of magnesium cations (Mg^2+) and bromide anions (Br^-). Magnesium bromide is commonly used in various chemical processes and as a medication for certain conditions.
YES!!!! It is an ionic combination of magnesium with bromine. 1 magnesium atom combines ionically with two 2 atoms of bromine. Mg(s) + Br2(l) = Mg^(2+) aq + 2Br^(-)aq = MgBr2(s)