In 'mgbr2' there are NO elements.
If you mean ' MgBr2'.
Then the elements are ;-
Magnesium (Mg)
Bromine (Br)
NB When writing chemical formulae, be it one or two letter symbol, the first letter is ALWAYS a CAPITAL letter. Hence my 'NO' for lower case letters.
MgBr2 is magnesium bromide. It is a combination of one cation ( atom) of magnesium and two anions( atoms of bromine.
The chemical formula of magnesium dibromide is MgBr2.
The reaction between Mg and Br2 results in the formation of MgBr2. The balanced chemical equation is: Mg + Br2 → MgBr2
MgBr2 is an ionic compound (salt: magnesium bromide)
Using a copy of the Periodic Table, showing the Atomic Masses. MgBr2 1 x Mg = 1 x 24 = 24 2 x Br = 2 x 80 = 160 24 + 160 = 184 the Mr ( Relative Molecular Mass) of tne molecule of MgBr2 Using the equation. moles = mass(g) / Mr Then mass(g = moles X Mt So for '7' moles mass(g) = 7 x 184 = 1288 g = 1.288 kg ( kilograms).
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
Two(2). They are ' Br^(2) ' . The terminal '2' indicates that there are two anions. NB Collectively they are IONS . Positively charged ions are ' CATIONS'. M^(n+) Negatively charged ions are ' ANIONS'. X^(n-) MgBr2 = Mg^(2+) ' positively charged cation 2Br^(-) ' negatively charged anions. For an ionic compound to be neutral , the charged MUST balance and be opposite. (+/-) Hence MgBr2 = 2+ for magnesium and "2 x -1 = -2 ' for the two bromines. Hence + 2 - 2 = 0
Magnesium (Mg) and Bromine (Br) - Magnesium Bromide - MgBr2
Using a copy of the Periodic Table, showing the Atomic Masses. MgBr2 1 x Mg = 1 x 24 = 24 2 x Br = 2 x 80 = 160 24 + 160 = 184 the Mr ( Relative Molecular Mass) of tne molecule of MgBr2 Using the equation. moles = mass(g) / Mr Then mass(g = moles X Mt So for '7' moles mass(g) = 7 x 184 = 1288 g = 1.288 kg ( kilograms).
Magnesium bromide
The chemical formula of magnesium dibromide is MgBr2.
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
The reaction between Mg and Br2 results in the formation of MgBr2. The balanced chemical equation is: Mg + Br2 → MgBr2
MgBr2 is an ionic compound (salt: magnesium bromide)
MgBr2 is soluble in water and other polar solvents.
Using the Avogadro Number, of 6.022 x 10^(23) = one mole Dividing 3.6000 x 10^(24) / 6.022 x 10^(23) = 5.97808.... moles.
Yes.The cation,Mg 2+bonds with the anions,2Br 2-to form,MgBr2------------------magnesium bromide