MgBr₂ contains three elements: magnesium (Mg), bromine (Br), and bromine again, as it has two bromine atoms. Therefore, while it consists of two types of elements, the total count of individual atoms is three.
In MgBr2, there are two bromide anions (Br-) for each magnesium cation (Mg2+), so the total number of anions in MgBr2 is 2.
The molar mass of MgCl2 = 95.211 g/mol
The chemical formula of magnesium dibromide is MgBr2.
The reaction between Mg and Br2 results in the formation of MgBr2. The balanced chemical equation is: Mg + Br2 → MgBr2
MgBr2 is an ionic compound (salt: magnesium bromide)
In MgBr2, there are two bromide anions (Br-) for each magnesium cation (Mg2+), so the total number of anions in MgBr2 is 2.
Magnesium (Mg) and Bromine (Br) - Magnesium Bromide - MgBr2
Is the following chemical equation balanced? MgI2 + Br2 MgBr2 + I2 yes no
The molar mass of MgCl2 = 95.211 g/mol
Magnesium bromide
The chemical formula of magnesium dibromide is MgBr2.
There are 0.021 moles of MgBr2 in 3.50 g. Since MgBr2 contains 2 bromide ions per formula unit, there are 0.042 moles of Br- ions. So, there are 0.042 * 6.022 x 10^23 = 2.53 x 10^22 Br- ions in 3.50 g of MgBr2.
There are a total of 2 moles of anions in 2.50 g of MgBr2. Each formula unit of MgBr2 contains 2 moles of anions (Br-). The molar mass of MgBr2 is 184.113 g/mol, so 2.50 g is equivalent to 0.0136 moles, and therefore 0.0136 moles * 2 moles = 0.0272 moles of anions.
The reaction between Mg and Br2 results in the formation of MgBr2. The balanced chemical equation is: Mg + Br2 → MgBr2
MgBr2 is soluble in water and other polar solvents.
MgBr2 is an ionic compound (salt: magnesium bromide)
The answer is 5,978 moles.