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By definition, one mole would be the same as the Atomic Mass. You take the number of moles and multiply it by the atomic mass. So if you have just 1 mole, the number of grams will be the atomic mass. Calcium's atomic mass is 40.08 grams.

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How many moles of ca would be in 3.8G?

3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============


How many grams are there in .761 moles of Ca?

For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca


How many grams is contained in .27 moles of calcium?

(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.


How many moles of calcium is 126g of ca?

126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------


How many grams of ca(no3) are needed to make a 250 ml of 0.50M solution?

To calculate the amount of Ca(NO3)2 needed for a 0.50M solution: Find the molar mass of Ca(NO3)2 = 164.09 g/mol. Calculate the number of moles needed: 0.50 moles/L x 0.250 L = 0.125 moles. Convert moles to grams: 0.125 moles x 164.09 g/mol ≈ 20.51 grams of Ca(NO3)2 are needed.


How many moles are in forty grams of calcium?

For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.40.0 grams Ca / (40.08 grams) = .998 moles Ca


How many grams of CaOH2 are needed to prepare 300.0 mL of a 0.115 M solution?

Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed


What is the mass of 3.61 moles of Ca?

Well, darling, the molar mass of calcium (Ca) is approximately 40.08 g/mol. So, if you have 3.61 moles of Ca, you just need to multiply the molar mass by the number of moles to find the mass. In this case, 3.61 moles of Ca would have a mass of around 144.88 grams. Hope that clears things up for you, sugar!


How many moles of calcium ca atoms are in 98.5 g of ca?

To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.


How many moles of calcium are in 5000 grams of calcium?

To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.


How many moles of calcium are there in 77.4 grams of Ca?

To find the number of moles, you need to divide the given mass of calcium by its molar mass. The molar mass of calcium (Ca) is approximately 40.08 g/mol. Number of moles = 77.4 g / 40.08 g/mol ≈ 1.93 moles.


How many grams are in 0.658 mole of calcium phosphate?

To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.