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To find the grams of KMnO4 in a 0.2N solution, you need the equivalent weight of KMnO4, which is approximately 158.04 g/mol divided by 5 (since one mole of KMnO4 provides 5 equivalents for redox reactions). Therefore, the equivalent weight is about 31.61 g/equiv. For a 1-liter solution, 0.2N means there are 0.2 equivalents, which translates to about 6.32 grams of KMnO4 (0.2 eq × 31.61 g/equiv).
What else can I help you with?
How many grams of KMnO4 should be used to prepare 2L of a 5M solution?
To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.
How many grams of EDTA do you add to make a 3.7 percent EDTA solution?
To make a 3.7% EDTA solution, you would add 3.7 grams of EDTA to 100 mL of solution.
How many grams of magnesium sulfate are in 300ml of a 120 magnesium solution?
To find the grams of magnesium sulfate in a 300 mL solution with a concentration of 120 mg/mL, you can multiply the concentration by the volume of the solution. This is calculated as follows: 120 mg/mL × 300 mL = 36,000 mg. To convert this to grams, divide by 1,000, resulting in 36 grams of magnesium sulfate in the solution.
How many grams of NaCl would you recover if you evaporated all of the water off of this solution?
This depends on the volume and concentration of this solution.
How many grams of NaOH are in 750 ml 0.600 M NaOH solution?
This solution contain 26,3 g NaOH.
How many grams KMnO4 take in 0.1N KMnO4 solution?
(158 g = 1 mole) --- molar mass of potassium permanganate. You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.
How many grams of KMnO4 should be used to prepare 2L of a 5M solution?
To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.
How many grams of potassium permanganate KMnO4 are in 2.55 moles?
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
How many moles of KMnO4 are present in 75.0 mL of a 0.0950 M solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
How many 60 mg kmno4 tablets are needed to make following solution kmno4 1 5000 600 ml?
2 TABLETS
How many grams of potassium permanganate are in 2.20 moles?
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
How many moles are in KMnO4?
the charge in KMno4 is zero . it has no unpaired electrons but it is still dark in colored due to charge transfer in KMnO4. from Ayushi Sharma
How many grams of sugar must be added to 60 grams of a solution that is 32 percent sugar to obtain a solution that is 50 percent sugar?
40.8 grams
How many grams of hcl are contained in 4 liters of a 12m solution?
438 grams.
How many Grams of Phosphate are in a 50 percent K2HPO4 Solution?
To calculate the grams of phosphate in a solution, you first need to determine the molarity of the solution. Once you know the molarity, you can use the molecular weight of phosphate to determine the grams present in the solution. Can you provide the concentration or volume of the K2HPO4 solution?
If you have 17.34 moles of potassium permanganate how many kilograms of the substance do you have?
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
