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I need help with this! the problem says
"Thimerosal is an organic compound (gram-molecultar mass = 404.8 g/mol). A .100% solution of thimerosal is sometimes used as an antiseptic. Assume that this solution has a density of 1.00 g/mL."
I need help with these two:
What mass of thimerosal must be mixed with 25.0 g of water to make a .100% solution?
What volume of 0.100% solution contains 0.750 g of thimerosal?
What else can I help you with?
What is the percentage by mass of salt solution prepared by dissolving 11 grams of salt in 80 grams of solution with solution?
The percent concentration is 13,75 %.
How much solute is required to create 100 mL of 12 percent wv solute?
To create a 12% weight/volume (w/v) solution, you need 12 grams of solute for every 100 mL of solution. Therefore, for 100 mL of a 12% w/v solution, you would require 12 grams of the solute.
How many grams of EDTA do you add to make a 3.7 percent EDTA solution?
To make a 3.7% EDTA solution, you would add 3.7 grams of EDTA to 100 mL of solution.
How do you make a 10 percent of KI solution?
To make a 10% KI solution, dissolve 10 grams of potassium iodide (KI) in 90 grams of water, for a total of 100 grams of solution. This will give you a 10% weight/volume (w/v) solution of KI.
What is another way to express the concentration of a glucose solution that is 0.01 percent by weight?
Another way to express the concentration of a 0.01 percent by weight glucose solution is to say it is a 100 parts per million (ppm) solution. This means there are 100 grams of glucose in every 1 million grams of solution.
How many grams of sugar must be added to 60 grams of a solution that is 32 percent sugar to obtain a solution that is 50 percent sugar?
40.8 grams
What is the percentage by mass of salt solution prepared by dissolving 11 grams of salt in 80 grams of solution with solution?
The percent concentration is 13,75 %.
How many grams of dextrose will 1000 ml of a 10 percent solution contain?
A 10 percent solution of dextrose means that there are 10 grams of dextrose per 100 milliliters of solution. Therefore, in 1000 milliliters (which is 10 times 100 ml), there would be 10 grams x 10 = 100 grams of dextrose in a 1000 ml solution.
What is the weight of 10 percent acetic acid?
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
What is meant by the mass mass percent concentration of a solution?
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
How many grams of NaCl are in 225 grams of an 18 percent NaCl solution?
The answer is 8 g NaCl.
What is the mass percent of a solution prepared by dissolving 18.9 grams of solid into 39.5 grams of water?
32.4
How do you prepare 30 percent sucrose solution?
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
How much glucose in 25 percent solution?
A 25 percent glucose solution means that there are 25 grams of glucose in every 100 milliliters of the solution. Therefore, in 25 milliliters of a 25 percent glucose solution, there would be 6.25 grams of glucose. This concentration is commonly used in medical and laboratory settings for various applications.
How many grams of salt in 200 g of a 10.0 percent mass solution?
200 grams X 0.10 = 20 grams
How many grams of NaCl are required to prepare 4000 mL of 5 percent solution?
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
How many grams of active ingredient will you need to prepare 2.5 gallons of a 45.6 percent solution?
4314.9 grams
