One mole equals 22.4 liters. This is only at STP (Standard temperature and pressure!)
One mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, one mole of helium would also occupy 22.4 liters at STP.
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
Using the ideal gas law, at STP (standard temperature and pressure), 1 mole of gas occupies 22.4 liters. Therefore, a balloon with 560 liters at STP would contain 25 moles of gas (560 liters / 22.4 liters/mole).
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
At standard temperature and pressure (STP), one mole of gas occupies 22.4 liters. To find the number of moles in 15.7 liters of chlorine gas, divide 15.7 liters by 22.4 liters/mole, which gives approximately 0.699 moles. Since one mole contains Avogadro's number of molecules (approximately (6.022 \times 10^{23}) molecules/mole), the total number of molecules is about (0.699 \times 6.022 \times 10^{23} \approx 4.21 \times 10^{23}) molecules.
1 mole = 22.414 liters So, 3.5 mole = 78.45 liters
One mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. Therefore, one mole of helium would also occupy 22.4 liters at STP.
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
Using the ideal gas law, at STP (standard temperature and pressure), 1 mole of gas occupies 22.4 liters. Therefore, a balloon with 560 liters at STP would contain 25 moles of gas (560 liters / 22.4 liters/mole).
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. Therefore, 1 mole of helium (He) gas would occupy 22.4 liters at STP.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
At standard temperature and pressure (STP), one mole of gas occupies 22.4 liters. To find the number of moles in 15.7 liters of chlorine gas, divide 15.7 liters by 22.4 liters/mole, which gives approximately 0.699 moles. Since one mole contains Avogadro's number of molecules (approximately (6.022 \times 10^{23}) molecules/mole), the total number of molecules is about (0.699 \times 6.022 \times 10^{23} \approx 4.21 \times 10^{23}) molecules.
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At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
There are always ONE mole of gas in 22,4 L gas of any kind (even gaseous mixtures like air) at stp.So 68.5 (L) / 22.4 (L/mole) = 3.06 mole gas in 68.5 L (at STP)