For this you need the atomic (molecular) mass of C6H5OH. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. C6H5OH=94.1 grams
25.5 grams C6H5OH / (94.1 grams) = .271 moles C6H5OH
Approx. 0,007 moles.
The answer is 0,4 moles.
978 g calcium contain 24,4 moles.
14,84 g magnesium are equivalent to 0,61 moles.
67,4 g HCl is equivalent to 1,85 moles.
573,28 of g of AgCI is equivalent to 4 moles.
125 g nickel is equivalent to 2,13 moles.
The equivalent of 125 g zinc is 1, 91 moles.
There are 58.6934 gram in one mole of Ni atoms, so there are125(g Ni) / 58.6934 (g.mol-1 Ni) = 2.13 moles in 125 gram Ni
3,80 g Zn have 0,058 moles.
The formula is: number of moles = g Be/9,012.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The answer is 0,253 moles.
The answer is 0,4 moles.
The answer is 0,364 moles.
573,28 of g of AgCI is equivalent to 4 moles.
978 g calcium contain 24,4 moles.
14,84 g magnesium are equivalent to 0,61 moles.