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How many grams in 5.0x1022 molecules of nitrogen monoxide?

To find the number of grams in 5.0x10^22 molecules of nitrogen monoxide (NO), you need to convert the number of molecules to moles and then from moles to grams. First, calculate the number of moles by dividing the number of molecules by Avogadro's number (6.022x10^23 molecules/mol). Then, use the molar mass of NO (30.01 g/mol) to convert moles to grams.


When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form how many grams of water form?

the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.


How many moles in 22 grams of argon?

55.64


How many atoms of nitrogen are present in 1.00 g of nitrogen?

first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23 n(N)=1/14 * 6.02*10^23 =4.2*10^22 atoms


How do you convert 2.2 grams in to atoms in nitrogen?

To convert grams to atoms, you need to first convert grams of nitrogen to moles using its molar mass (14.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, for 2.2 grams of nitrogen: Convert grams to moles: 2.2 g / 14.01 g/mol = 0.157 moles. Convert moles to atoms: 0.157 moles x 6.022 x 10^23 atoms/mol = 9.46 x 10^22 atoms of nitrogen.


How many moles does a sample of CO2 that contains 8.16x1022 O atoms?

if you mean 10^22 O atoms, then this is how you do it: (8.16X10^22)/2=4.08X10^22 so there are 4.08X10^22 molecules, divided by 6.022X10^23(1 mole) is .06775, so there are that many moles of CO2. If you wanted to know how many moles of overall atoms there were, there's 4.08X10^22 molecules, 1 C in each so 4.08X10^22 C, and 8.16X10^22 O=1.224X10^23, and that's how many atoms, so that divided by 1 mole is (most accurate answer i can get you) .2032547326 moles of atoms so .2032547326 moles of atoms or .06775 moles of molecules/CO2


How many Na atoms are there in 0.125 moles of Na metal?

0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms


How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?

To determine the number of moles of fluorine present in 2.67 grams of nitrogen trifluoride (NF3), we first need to calculate the molar mass of NF3, which is 71.0 g/mol. Then we find the moles of NF3 in 2.67 g by dividing the mass by the molar mass: 2.67 g / 71.0 g/mol ≈ 0.038 moles. As there are three fluorine atoms in each molecule of NF3, there are 3 times more moles of fluorine: 0.038 moles NF3 x 3 = 0.114 moles of fluorine.


How many moles of Mg is 2.01 times 10x22 atoms?

2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles


If 5 moles of P4 reacted with 22 moles Cl2 according to the above reaction determine how many moles PCl3 are produced?

The reaction between phosphorus (P4) and chlorine (Cl2) to form phosphorus trichloride (PCl3) can be represented by the equation: ( P_4 + 6 Cl_2 \rightarrow 4 PCl_3 ). From the stoichiometry, 1 mole of P4 reacts with 6 moles of Cl2 to produce 4 moles of PCl3. Given 5 moles of P4 and 22 moles of Cl2, the limiting reactant is Cl2 because 5 moles of P4 would require 30 moles of Cl2. Thus, with 22 moles of Cl2 available, the maximum amount of PCl3 produced is calculated as follows: ( \frac{22 \text{ moles } Cl_2}{6} \times 4 = \frac{88}{6} \approx 14.67 \text{ moles of PCl3} ).


How many moles of iron are contained in 5.22 x 10 to the power of 22?

To find the number of moles, you need to divide the given number of iron atoms by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. Therefore, for 5.22 x 10^22 iron atoms, the number of moles would be approximately 0.0867 moles.


What is the mass of 2.84 x 1022 molecules of nitrogen gas?

To calculate the mass of 2.84 x 10^22 molecules of nitrogen gas, you first need to convert molecules to moles using Avogadro's number. Then, you can use the molar mass of nitrogen (28.02 g/mol) to determine the mass. The mass of 2.84 x 10^22 molecules of nitrogen gas would be approximately 5.04 grams.