To determine the number of molecules in 45 g of silver, you first need to calculate the number of moles of silver using its molar mass (107.87 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
45/94.2 is 0.4777 moles
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
To determine the number of molecules in 45 g of silver, you first need to calculate the number of moles of silver using its molar mass (107.87 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
45/94.2 is 0.4777 moles
The formula is: number of moles = g Be/9,012.
27.4 g H2O x 1 mole/18 g = 1.52 moles
978 g calcium contain 24,4 moles.
29,0 g of calcium is equal to 0,723 moles.
67,4 g HCl is equivalent to 1,85 moles.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
573,28 of g of AgCI is equivalent to 4 moles.
First of all we convert the mass of leadto moles. Using the equation moles = mass(g) / Ar (Realtive atomic Mass)_. Mass( g) = 45 g Ar =~ 207 (Periodic Table). Hence moles(Pb) = 45 x 207 Moles (Pb) = 9315 moles. Next using the Avogadro number. 1 moles(of A SUBSTANCE) contains 6.022 x 10^(23) atoms. Hence number of atoms in 9315 moles = 9315 x 6.022 x 10^(23) = 5.61 x 10^(27) atoms. As a 'silly' number. 5,610,000,000,000,000,000,000,000,000 atoms.
156 g calcium is equivalent to 3,89 moles.