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To calculate the heat needed to boil 38.0 g of water, we use the formula ( q = m \times L_v ), where ( m ) is the mass of the water and ( L_v ) is the latent heat of vaporization of water (approximately 2260 J/g). First, convert the mass to kilograms: 38.0 g = 0.038 kg. Then, calculate the heat: ( q = 38.0 , \text{g} \times 2260 , \text{J/g} = 85,880 , \text{J} ) or 85.88 kJ. Thus, approximately 85.9 kJ of heat is needed to boil 38.0 g of water.

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AnswerBot

1mo ago

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