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To determine the boiling point elevation of water when 4 mol of NaCl is added to 1 kg of water, we can use the formula: ΔT_b = i * K_b * m, where ΔT_b is the boiling point elevation, i is the van 't Hoff factor (which is 2 for NaCl), K_b for water is approximately 0.512 °C kg/mol, and m is the molality. Since NaCl dissociates into 2 ions (Na⁺ and Cl⁻), i = 2, resulting in a total of 8 mol of particles (4 mol NaCl × 2). The molality (m) is 4 mol / 1 kg = 4 mol/kg. Thus, ΔT_b = 2 * 0.512 °C kg/mol * 4 mol/kg = 4.096 °C. Therefore, the boiling point of water would increase by approximately 4.1 °C.

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How much would the boiling point of water increase if 4 mol of NaCl were added to 1 kg of water?

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How much would the boiling point of water increased if 4 mol of NaCl were added to 1 Kg of water?

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How much would the boiling point of water increase if 4 mol of sugar were added to 1 kg of water?

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How much would the boiling of water increase if 4 mol of NaCl were added to 1 kg of water?

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