To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
To determine the energy produced from 8.52 moles of oxygen, we need to know the specific reaction taking place, as different reactions yield different amounts of energy. For example, in cellular respiration, the complete oxidation of one mole of glucose (which requires 6 moles of oxygen) produces about 2870 kJ of energy. If we assume a similar reaction, we could calculate the energy based on the stoichiometry of the reaction and the energy yield per mole of oxygen. Without additional details about the specific reaction, we cannot provide an exact energy value.
The compound 2NaCl + Br2 is not a specific compound itself. It represents a chemical reaction where two moles of sodium chloride (NaCl) react with one mole of bromine (Br2). The products of this reaction would be sodium bromide (NaBr) and possibly other byproducts depending on reaction conditions.
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
-14 J/Mol
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
84 J/6 moles = 14 J/mole = ∆H
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
The compound 2NaCl + Br2 is not a specific compound itself. It represents a chemical reaction where two moles of sodium chloride (NaCl) react with one mole of bromine (Br2). The products of this reaction would be sodium bromide (NaBr) and possibly other byproducts depending on reaction conditions.
-14 J/mol
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.