To find the mass of 1.25 x 10^-8 mol of Cl2, you first need the molar mass of Cl2, which is approximately 70.9 g/mol (since the Atomic Mass of chlorine is about 35.45 g/mol). Multiply the number of moles by the molar mass:
[ \text{Mass} = 1.25 \times 10^{-8} , \text{mol} \times 70.9 , \text{g/mol} \approx 8.86 \times 10^{-7} , \text{g}. ]
So, the mass of 1.25 x 10^-8 mol of Cl2 is approximately 8.86 x 10^-7 grams.
# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol
The mass in grams of 5,01 mol of xenon is 657,778 g.
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
1.9 mol Se ( 78.96 grams/1mol Se ) = 150.024 grams
To calculate the mass of 0.00844 mol of NiSO4, you need to know the molar mass of NiSO4. It is 154.756 g/mol. So, multiply the number of moles (0.00844) by the molar mass (154.756 g/mol) to get the mass in grams, which is approximately 1.30 grams of NiSO4.
To find the number of moles in 79.3g of Cl2, first determine the molar mass of Cl2 (35.5g/mol x 2 = 71g/mol). Next, divide the given mass by the molar mass to get the number of moles (79.3g / 71g/mol = 1.12 moles of Cl2).
The molar mass of chlorine gas (Cl2) is 70.91 g/mol. To convert grams to moles, you divide the mass (84 g) by the molar mass (70.91 g/mol). So, 84 grams of chlorine gas is equal to approximately 1.18 moles.
To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
# of Moles = Mass in grams divided by Molar Mass =5o divided by (cl x 2) =50 divided by 71 =0.704 moles use: 1 mol = Mr in grams that is 35.5x2 g of Cl2 = 1 mol 71g of Cl2 = 1 mol therefore 50g of Cl2 = (1/71) x 50 =0.704 mol
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
The mass in grams of 5,01 mol of xenon is 657,778 g.
To find the mass in grams of 0.330 mol of calcium, you need to multiply the number of moles by the molar mass of calcium. The molar mass of calcium is approximately 40.08 grams/mol. So, 0.330 mol * 40.08 g/mol = 13.23 grams of calcium.
The molar mass of carbon is approximately 12 grams/mol. Therefore, the mass of 2 moles of 12C is 24 grams (12 g/mol x 2 mol).
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
So, you're given 75.0 grams of C2H2Cl4 and you want to find how many L of Cl2. Reaction: 2Cl2 + C2H2 --> C2H2Cl4 Understand the information you need to fill your conversion factor. You'll want to know: how many grams are in 1 mol C2H2Cl4 (167.84 g)[added atomic weight from periodic table] mole to mole ratio of Cl2 and C2H2Cl4 (2:1)[given in reaction] how many liters are in a mole (22.4 L/mol)[universal] Then, you want to set up your conversion factor. 75.0 g C2H2Cl4 x ( 1 mol C2H2Cl4/ 167.84 g C2H2Cl4 ) x (2 mol Cl2/1 mol C2H2Cl4) x (22.4 L/ 1 mol) = ?