Ag H2O typically refers to silver(I) hydroxide, which can be represented as AgOH, but in this context, it may imply a silver ion (Ag⁺) in aqueous solution. Silver ions can interact with water molecules, forming complexes or participating in various chemical reactions. Silver is known for its antimicrobial properties and is used in various applications, including medicine and water purification.
First we have to figure out which species is oxidized and which is reduced and balance it in acid solution. On the left side, Ag has an oxidation number of 0 (it is an uncombined element). On the right side, Ag is +1. Why? Ag = +1 + 2CN- = -2 ----------------------------- Ag(CN) ion charge = -1 Note that oxygen on the left side also has an oxidation number of 0 for the same reason as Ag. But on the right side of the equation, it has formed H2O and has a charge of -2. CN- is really a spectator ion (isn't oxidized or reduced) so we can ignore it for now. Let's balance each half-reaction. I'm using = as an arrow sign. Oxidation: Ag = Ag+ + e- (done) Reduction: O2 = H2O Put a 2 in front of H2O O2 = 2H2O to balance oxygen Put 4H+ on the left side O2 + 4H+ = 2H2O to balance hydrogen Put 4e- on the left to O2 + 4H+ + 4e- = 2H2O To add the oxidation and reduction reactions together, I need to multiply the oxidation reaction by 4 so its electrons will cancel with the four that are in the reduction reaction. Doing that you get 4Ag + O2 + 4H+ = 4Ag+ + 2H2O In alkaline solution, you find the H+ above and add an equal number of OH- to BOTH sides of the equation: The 4H+ + 4OH- give 4 H2O. 4Ag + O2 + 4H+ = 4Ag+ + 2H2O +4OH- + 4OH- --------------------------------------... 4H2O If I delete two H2O from each side I get: 4Ag + O2 + 2H2O = 4Ag+ + 4OH- Finally, I can add 2CN- to each side for this: 4Ag + O2 + 2H2O + 8CN- = 4Ag(CN)- + 4OH-
When an excess of AgNO3 solution is added to a one molar solution of CrCl(H2O)5Cl2, all the chloride ions (Cl⁻) from CrCl(H2O)5Cl2 will react with Ag⁺ ions to form AgCl precipitate. Since CrCl(H2O)5Cl2 contains 6 moles of Cl⁻ per mole of complex, the reaction will precipitate 6 moles of AgCl. Therefore, 6 moles of AgCl will be formed.
Ag is the element Silver. Ag has more electrons than Ag+as for the element to become positively charged through a process called oxidation in which Ag has given up an electron to another element in order to obtain a positive charge. Another way to look at it is the "+" indicates a loss of a negatively charged particle which, in this case, is an electron. Proper Half-Reaction: Ag+ + e- ---> Ag
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Silver (Ag) does not react with water (H2O) under normal conditions because silver is relatively unreactive. However, silver can react with water containing dissolved oxygen or other reactive substances to form silver oxide compounds.
When silver nitrate (AgNO3) is dissolved in water (H2O), it dissociates into silver ions (Ag+) and nitrate ions (NO3-). Therefore, the solution contains silver ions and nitrate ions but no hydrogen ions (H+).
AgNO3 H2O is a compound of silver nitrate and water. When AgNO3 dissolves in water, it ionizes into silver ions (Ag+) and nitrate ions (NO3-). The silver ions can participate in various chemical reactions such as precipitation or complexation reactions.
Half equations: CH2O + 2OH- ---> CH2O2 + H2O + 2e [Ag(NH3)2]+ + e ---> Ag + 2NH3 Full equation: CH2O + 2OH- + 2[Ag(NH3)2]+ ---> CH2O2 + H2O + 2Ag + 4NH3 The aldehyde shown is methanal. Same equation for any aldehyde, just replace CH2O with the relevant molecule and balance.
(2 Na+ + HS- + OH-)(aq) + 2 (Ag+ + [NO3]-)(aq) ---------- Ag2S(S) + 2 (Na+ + [NO3]-)(aq) + H2O
First we have to figure out which species is oxidized and which is reduced and balance it in acid solution. On the left side, Ag has an oxidation number of 0 (it is an uncombined element). On the right side, Ag is +1. Why? Ag = +1 + 2CN- = -2 ----------------------------- Ag(CN) ion charge = -1 Note that oxygen on the left side also has an oxidation number of 0 for the same reason as Ag. But on the right side of the equation, it has formed H2O and has a charge of -2. CN- is really a spectator ion (isn't oxidized or reduced) so we can ignore it for now. Let's balance each half-reaction. I'm using = as an arrow sign. Oxidation: Ag = Ag+ + e- (done) Reduction: O2 = H2O Put a 2 in front of H2O O2 = 2H2O to balance oxygen Put 4H+ on the left side O2 + 4H+ = 2H2O to balance hydrogen Put 4e- on the left to O2 + 4H+ + 4e- = 2H2O To add the oxidation and reduction reactions together, I need to multiply the oxidation reaction by 4 so its electrons will cancel with the four that are in the reduction reaction. Doing that you get 4Ag + O2 + 4H+ = 4Ag+ + 2H2O In alkaline solution, you find the H+ above and add an equal number of OH- to BOTH sides of the equation: The 4H+ + 4OH- give 4 H2O. 4Ag + O2 + 4H+ = 4Ag+ + 2H2O +4OH- + 4OH- --------------------------------------... 4H2O If I delete two H2O from each side I get: 4Ag + O2 + 2H2O = 4Ag+ + 4OH- Finally, I can add 2CN- to each side for this: 4Ag + O2 + 2H2O + 8CN- = 4Ag(CN)- + 4OH-
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If Ag+ is converted to Ag, it has gained electrons. Ag+ indicates that silver has lost one electron, so when it is converted back to Ag, it means that electron has been gained back.
Silver nitrate is the chemical name for the molecular compound having formula AgNO3. It is composed of silver (Ag) and a nitrate group (NO3). The reaction for its disassociation into water (H2O) is:AgNO3(s) + H20(l) <--> Ag+ (aq) + NO3-(aq) + H2O(l)
Образуется растворимое комплексное соединение: AgBr + 2 NH4OH -----> [Ag(NH3)2]+ + Cl- + 2 H2O.
Ag is the symbol for the element silver.
AG stands for Aktiengesellschaft = stock corporation.