Pb + CrCl2 = PbCl2 + Cr
considered a redox single replacement and the Cr has a +2 charge so we assume the Pb also has a +2 because it is a transition metal
The yield is 82,45 %.
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
When you mix Pb2+ and OH-, they will react to form a precipitate of lead (II) hydroxide, which has the chemical formula Pb(OH)2. This is an insoluble compound that will form a solid or a cloudy solution.
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
Lead dioxide can be produced from lead carbonate by heating the lead carbonate in the presence of oxygen to convert it to lead oxide, then further heating the lead oxide in the presence of oxygen to convert it to lead dioxide. This process involves two steps of thermal decomposition and oxidation to yield lead dioxide.
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The name of CrCl2 is chromium (II) chloride.
Lead reacts with hydrogen nitrate to form lead(II) nitrate and hydrogen gas. The balanced chemical equation for this reaction is: Pb + 4HNO3 → Pb(NO3)2 + 2H2
void swap (int &pa, int &pb) { *pa ^= *pb; *pb ^= *pa; *pa ^= *pb; }
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The yield is 82,45 %.
2 PbO + C -> 2 Pb + CO2
NI(NO3)3+pbbr4nibr3+pb(no3)4
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Pb which is neutral has 82 electrons. Thus, if it has a 4+ charge, then it has 78 electrons.
Lead (II)