Pb + CrCl2 = PbCl2 + Cr
considered a redox single replacement and the Cr has a +2 charge so we assume the Pb also has a +2 because it is a transition metal
The yield is 82,45 %.
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
When you mix Pb2+ and OH-, they will react to form a precipitate of lead (II) hydroxide, which has the chemical formula Pb(OH)2. This is an insoluble compound that will form a solid or a cloudy solution.
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
An acid plus a base will yield a salt and water in a neutralization reaction.
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The name of CrCl2 is chromium (II) chloride.
Lead reacts with hydrogen nitrate to form lead(II) nitrate and hydrogen gas. The balanced chemical equation for this reaction is: Pb + 4HNO3 → Pb(NO3)2 + 2H2
void swap (int &pa, int &pb) { *pa ^= *pb; *pb ^= *pa; *pa ^= *pb; }
The yield is 82,45 %.
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2 PbO + C -> 2 Pb + CO2
NI(NO3)3+pbbr4nibr3+pb(no3)4
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Pb which is neutral has 82 electrons. Thus, if it has a 4+ charge, then it has 78 electrons.
Lead (II)