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To convert 14 kg of hydrochloric acid (HCl) to liters, you need to know its density. The density of concentrated HCl is approximately 1.18 g/mL. Therefore, 14 kg of HCl is equivalent to 14,000 grams. Using the density, the volume in liters can be calculated as follows: Volume = Mass/Density = 14,000 g / 1.18 g/mL = approximately 11.86 liters.
What else can I help you with?
What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl and The answer is 1.64l so how do u solve it?
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
What is the molarity of a 1.50-liter solution containing 14 grams of HCl?
To find the molarity of the solution, first calculate the number of moles of HCl. The molar mass of HCl is approximately 36.46 g/mol, so 14 grams of HCl is about 0.384 moles (14 g ÷ 36.46 g/mol). Molarity (M) is defined as moles of solute per liter of solution, so the molarity of the solution is 0.384 moles ÷ 1.50 liters, which equals approximately 0.256 M.
How would you prepare 17.2 L of a 3.8 M HCl solution?
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
How many liters weigh 1 kg?
There are approximately 1.04 liters in one kilogram.
What is the molality of a solution that contains 31.0 grams of HCl in 500 grams of water?
31 g of HCl divided by the molar mass of HCl to find how many mols. HCl --> H(1) + Cl(1) = molar mass of HCl 1.008(1) + 35.45(1)= 36.428 molar mass 31/36.428= 2.97 which is the mols of solute The mols of solute divided by kg of solute = molality 2.97/.500= 1.7 molality
What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
What is the molarity of a solution of 73 g of HCL in 2 liters of water?
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
How many moles of HCl are present in 0.70 liters of a 0.33 M HCl solution?
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
How to convert kg over liters per second to kg over liters per hour?
1 (kg / liters) per second = 3600 (kg / liters) per hour. So, multiply kg/l per second by 3,600 to get kg/l per hour.
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl and The answer is 1.64l so how do u solve it?
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
160 liters equals how many pounds?
160 liters are exactly 352.739619 pounds. 1 liter is 1000 grams which is 1 kg. 160 liters are 160 kg's 160 kg's are 352.739619 pounds.
What is the molarity of a solution in which 0.597 moles of HCl are dissolved in 0.169 liters of solution?
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
14 liters 7 millimeters to liters?
still 14 liters miliMETERS have nothing to do with liters
Calculate the molarity of a hydrochloric acid solution that is 18.25 percent HCl by mass and has a density 1.2gmL?
First, calculate the mass of HCl in 100 g of the solution: 18.25% of 100 g is 18.25 g. Convert the volume to liters: 1.2 g/mL = 1.2 kg/L. Calculate molarity using the formula Molarity (M) = (moles of solute)/(volume of solution in liters), where moles of solute = mass of HCl in grams / molar mass of HCl and volume of solution = mass of solution in grams / density of solution in g/mL.
