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To convert 14 kg of hydrochloric acid (HCl) to liters, you need to know its density. The density of concentrated HCl is approximately 1.18 g/mL. Therefore, 14 kg of HCl is equivalent to 14,000 grams. Using the density, the volume in liters can be calculated as follows: Volume = Mass/Density = 14,000 g / 1.18 g/mL = approximately 11.86 liters.
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What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl and The answer is 1.64l so how do u solve it?
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
How would you prepare 17.2 L of a 3.8 M HCl solution?
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
How many liters weigh 1 kg?
There are approximately 1.04 liters in one kilogram.
How many liters in 173kg of water?
There are approximately 173 liters in 173 kg of water, as the density of water is 1 kg/L.
What is the molality of a solution that contains 31.0 grams of HCl in 500 grams of water?
31 g of HCl divided by the molar mass of HCl to find how many mols. HCl --> H(1) + Cl(1) = molar mass of HCl 1.008(1) + 35.45(1)= 36.428 molar mass 31/36.428= 2.97 which is the mols of solute The mols of solute divided by kg of solute = molality 2.97/.500= 1.7 molality
What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
What is the molarity of a solution of 73 g of HCL in 2 liters of water?
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
How many moles of HCl are present in 0.70 liters of a 0.33 M HCl solution?
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
How to convert kg over liters per second to kg over liters per hour?
1 (kg / liters) per second = 3600 (kg / liters) per hour. So, multiply kg/l per second by 3,600 to get kg/l per hour.
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl and The answer is 1.64l so how do u solve it?
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
How many moles of HCl are present in 40ml of a 0.035M solution?
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
160 liters equals how many pounds?
160 liters are exactly 352.739619 pounds. 1 liter is 1000 grams which is 1 kg. 160 liters are 160 kg's 160 kg's are 352.739619 pounds.
What is the molarity of a solution in which 0.597 moles of HCl are dissolved in 0.169 liters of solution?
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
14 liters 7 millimeters to liters?
still 14 liters miliMETERS have nothing to do with liters
Calculate the molarity of a hydrochloric acid solution that is 18.25 percent HCl by mass and has a density 1.2gmL?
First, calculate the mass of HCl in 100 g of the solution: 18.25% of 100 g is 18.25 g. Convert the volume to liters: 1.2 g/mL = 1.2 kg/L. Calculate molarity using the formula Molarity (M) = (moles of solute)/(volume of solution in liters), where moles of solute = mass of HCl in grams / molar mass of HCl and volume of solution = mass of solution in grams / density of solution in g/mL.
