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What is the mole ratio of O2 to C4H9OH?
To determine the mole ratio of O2 to C4H9OH, we need to look at the balanced chemical equation for the combustion of butanol (C4H9OH). The balanced equation is: [ C4H9OH + 6 O2 \rightarrow 4 CO2 + 5 H2O. ] From the equation, the mole ratio of O2 to C4H9OH is 6:1. Thus, for every mole of butanol, six moles of oxygen are required.
How many moles of P2 O5 are produced from 8.00 mole of O2?
The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
How many moles of H2 are required to react with 5.0 moles O 2?
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
How many atoms of O2 are in a 1.76sample of CO2?
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
In the balanced reaction shown the mole ratio of fe2S3 to O2 is?
To determine the mole ratio of Fe₂S₃ to O₂ in a balanced chemical reaction, you need to look at the coefficients in the balanced equation. For example, if the balanced equation is 4 Fe₂S₃ + 12 O₂ → 8 Fe₂O₃ + 6 SO₂, the mole ratio of Fe₂S₃ to O₂ would be 4:12, which simplifies to 1:3. Therefore, the mole ratio of Fe₂S₃ to O₂ is 1:3.
What is the mole ratio of O2 to C4H9OH?
To determine the mole ratio of O2 to C4H9OH, we need to look at the balanced chemical equation for the combustion of butanol (C4H9OH). The balanced equation is: [ C4H9OH + 6 O2 \rightarrow 4 CO2 + 5 H2O. ] From the equation, the mole ratio of O2 to C4H9OH is 6:1. Thus, for every mole of butanol, six moles of oxygen are required.
How many grams of o2 are needed to combine with 6.85g of P?
To find the amount of O2 needed to combine with 6.85g of P, we first need to balance the chemical equation for the reaction between P and O2 to determine the mole ratio. Once we have the mole ratio, we can calculate the amount of O2 needed in grams using the given mass of P.
What is the molar ratio of 02 to so2?
The molar ratio of O2 to SO2 in the reaction 2SO2 + O2 -> 2SO3 is 1:1. This means that one mole of O2 reacts with two moles of SO2 to produce two moles of SO3.
What is the total number of moles of NO produced when 1.0 mole of O2 is completely consumed?
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.
How many moles of P2 O5 are produced from 8.00 mole of O2?
The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
Will 27 grams of aluminium react completely with 24 grams of oxygen?
Do you mean this reaction? 4Al + 3O2 -> 2Al2O3 27 grams Al ( 1 mole Al/26.98 grams)(3 mole O2/4 mole Al)(32 grams O2/1 mole O2) = 24 grams oxygen -------------------------
What mass of NO2 is formed when NO reacts with 384g O2?
The balanced chemical equation for the reaction between NO and O2 is 2NO + O2 → 2NO2. This equation shows that 2 moles of NO are needed to react with 1 mole of O2 to form 2 moles of NO2. First, convert 384g O2 to moles using its molar mass. Then, calculate the mass of NO2 produced using the mole ratio from the balanced equation.
How many moles of H2 are required to react with 5.0 moles O 2?
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
How many atoms of O2 are in a 1.76sample of CO2?
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
Given the reaction 2 SO2 plus O2 --- 2 SO3 what is the molar ratio for O2 to SO3?
1:2, does this need explaining???? 1-O2 for every 2-SO3 thus 1:2
What amount of oxygen require to react one gram calcium?
This is a relatively simple question that can be answered using simple stochiometry. If we assume a few things: a) that pure elements are reacting, b) that oxygen is in its stable diatomic form, and c) that they are reacting on a 1 to 1 mole ratio; then the math is as follows: 1 g.O2 x (1 mole O2 / 32 grams per mole) x (1 mole Ca / 1 mole O2) x (40.078 grams per mole / 1 mole Ca) = XXX.XX grams of Ca Thus the amount of calcium that will react on a 1 to 1 mole ratio with one gram of diatomic oxygen (O2) is 1.252 grams of calcium
If 0.440 mole of HgO reacts how many moles of O2 will be produced?
1 mole of HgO produces 1 mole of O2 according to the balanced chemical equation for the reaction. Therefore, 0.440 moles of HgO will produce 0.440 moles of O2.
