.06x molar mass of zinc which is the Atomic Mass so 3.9228 g
To calculate the number of moles of zinc, use the formula: moles = mass (grams) / molar mass (grams/mol). The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, 125 grams of zinc is equal to 125 g / 65.38 g/mol, which is about 1.91 moles of zinc.
To find the number of moles of zinc, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of zinc is approximately 65.38 g/mol. Thus, for 125 g of zinc, the calculation would be 125 g / 65.38 g/mol, which equals approximately 1.91 moles of zinc.
To determine the number of moles in 1 g of zinc nitrate, you need to know the molar mass of zinc nitrate. Zinc nitrate has a molar mass of 189.36 g/mol. By dividing 1 g by the molar mass, you can calculate that there are approximately 0.0053 moles of zinc nitrate in 1 g.
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
To find the mass of hydrogen produced from 120 moles of zinc reacting with hydrochloric acid, we first note the balanced chemical reaction: [ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 ] From the reaction, 1 mole of zinc produces 1 mole of hydrogen gas. Therefore, 120 moles of zinc will produce 120 moles of hydrogen. The molar mass of hydrogen (H₂) is approximately 2 grams per mole, so the mass of hydrogen produced is: [ 120 , \text{moles} \times 2 , \text{g/mole} = 240 , \text{grams} ]
To find the number of moles of zinc in 15 grams, divide the given mass by the molar mass of zinc. The molar mass of zinc is approximately 65.38 g/mol. Therefore, 15 grams of zinc is equal to 0.23 moles of zinc.
To calculate the number of moles of zinc, use the formula: moles = mass (grams) / molar mass (grams/mol). The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, 125 grams of zinc is equal to 125 g / 65.38 g/mol, which is about 1.91 moles of zinc.
To find the number of moles of zinc, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of zinc is approximately 65.38 g/mol. Thus, for 125 g of zinc, the calculation would be 125 g / 65.38 g/mol, which equals approximately 1.91 moles of zinc.
To determine the number of moles in 1 g of zinc nitrate, you need to know the molar mass of zinc nitrate. Zinc nitrate has a molar mass of 189.36 g/mol. By dividing 1 g by the molar mass, you can calculate that there are approximately 0.0053 moles of zinc nitrate in 1 g.
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
To find the mass of 4.35x10^-2 moles of zinc chloride (ZnCl2), you need to multiply the number of moles by the molar mass of ZnCl2. The molar mass of ZnCl2 is 136.3 g/mol. Therefore, the mass of 4.35x10^-2 moles of ZnCl2 would be 5.93 grams.
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
To determine the number of molecules produced, we first need to convert the mass of zinc (2.5g) to moles using the molar mass of zinc. Then, we calculate the number of moles of zinc reactant that reacted. From the balanced chemical equation, we can see that one mole of zinc produces one mole of zinc chloride molecules. Finally, we can use Avogadro's number to convert moles of molecules to actual molecules.
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
The equivalent of 125 g zinc is 1, 91 moles.
To find the mass of hydrogen produced from 120 moles of zinc reacting with hydrochloric acid, we first note the balanced chemical reaction: [ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 ] From the reaction, 1 mole of zinc produces 1 mole of hydrogen gas. Therefore, 120 moles of zinc will produce 120 moles of hydrogen. The molar mass of hydrogen (H₂) is approximately 2 grams per mole, so the mass of hydrogen produced is: [ 120 , \text{moles} \times 2 , \text{g/mole} = 240 , \text{grams} ]
To find the amount in moles of 3.80g of zinc (Zn), you need to divide the mass by the molar mass of Zn, which is approximately 65.38 g/mol. 3.80g Zn / 65.38 g/mol ≈ 0.058 moles Zn