answersLogoWhite

0

P = 31 mass weight

H = 1 mass weight, times that by 3 to get 3 (you do this because you have PH3)

Add both mass weights to get 34, then multiply that by the number of mols you have

34 x 3.91 mol = 130 g

User Avatar

JoZi

Lvl 2
3y ago

What else can I help you with?

Related Questions

How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?

The balanced chemical reaction is: 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O We use the reaction and the amount of the reactant , NH3, to determine the amount of oxygen needed. We do as follows: 200 g NH3 ( 1 mol / 17.04 g) (5 mol O2 / 4 mol NH3) (32 g / 1 mol) = 469.48 g O2 needed


What gas is heavier ammonia or oxygen?

Oxygen (1,429 g/cm3) is more dense than ammonia (o,70 g/cm3).


What is the mass of a 32 mol gold coin?

To find the mass of a 32 mol gold coin, you would first need to know the molar mass of gold, which is approximately 197 g/mol. Then, you can calculate the mass by multiplying the number of moles by the molar mass: 32 mol * 197 g/mol = 6304 g.


What is the mass in grams of 0.75 mol of sulfur which has a molar mass of approximately 32g mol?

The mass of 0.75 mol of sulfur can be calculated by multiplying the number of moles by the molar mass. Therefore, the mass would be 0.75 mol x 32 g/mol = 24 grams.


How many grams of oxygen are needed to react completely with 200.0 g of ammonia NH3?

The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.


How much mass does 1 mol of o2 gas have?

15.99 x 2 g


What is the mass percent of oxygon (O) in SO2?

The molar mass of SO2 is 64.06 g/mol. Oxygen contributes 32 g/mol to this molar mass, so the mass percent of oxygen in SO2 is (32 g/mol / 64.06 g/mol) x 100, which is approximately 50%.


How much NH3 is needed to react exactly with 21 grams of CH3OH?

To calculate the amount of NH3 needed to react with 21 grams of CH3OH, you first need to balance the chemical equation for the reaction. Then, you convert the mass of CH3OH to moles and use the mole ratio from the balanced equation to determine the moles of NH3 required. Finally, convert the moles of NH3 to grams using the molar mass of NH3.


What is the formula mass of CaSO4?

The formula mass of CaSO4 is calculated by adding the atomic masses of each element in the compound. Ca has an atomic mass of 40 g/mol, S has an atomic mass of 32 g/mol, and O has an atomic mass of 16 g/mol. So, the formula mass of CaSO4 is 40 + 32 + (4 x 16) = 136 g/mol.


What number of grams of NH3 produced by the reaction of 3.5g of hydrogen gas with sufficient nitrogen gas?

Assuming you mean the decomposition of ammonia: 2NH3 --> N2 + 3H2, 100g NH3 = 5.88mol (100/17), and the ratio of ammonia to nitrogen is 2:1. 5.88mol/2=2.94mol, so that's the amount of nitrogen produced. 2.94x28 (molar mass of N2) gets you 82.3g nitrogen produced.


What are the masses of molecular oxygen O2 hydrogen H2 and nitrogen in grams?

The molar mass of O2 is 32 g/mol, H2 is 2 g/mol, and N2 is 28 g/mol. To calculate the mass in grams, you would multiply the molar mass by the number of moles of the substance. For example, for 1 mole of O2, the mass would be 32 grams.


One mole of sulfur atoms has how much mass?

One mole of sulfur atoms has a mass of approximately 32 grams. This is based on the molar mass of sulfur, which is 32 g/mol.