1M
This is just easy. MOLARITY OF THIS COMPOUND IS 3MOLDM-3.
To find the molarity of BaCl₂, first calculate the molar mass of BaCl₂: barium (Ba) is approximately 137.33 g/mol and chlorine (Cl) is about 35.45 g/mol. Thus, the molar mass of BaCl₂ is 137.33 + 2(35.45) = 208.23 g/mol. Next, convert grams to moles: 416.48 g ÷ 208.23 g/mol ≈ 2.00 moles. Finally, the molarity (M) is calculated by dividing the number of moles by the volume in liters: 2.00 moles ÷ 2 L = 1.00 M.
Drinking 2L of water daily helps maintain hydration, supports body functions like digestion and temperature regulation, and aids in waste removal through urine. It can also improve skin health, energy levels, and overall well-being.
Use c1*V1=c2*V2 to calculate:(this goes for ANY molarity, not only for acetic acid as questioned)5(M) * 2(L) = x(M) * 7.5(L) , so x = molarity of the diluted = 1.3 M
92.4 grams
This is just easy. MOLARITY OF THIS COMPOUND IS 3MOLDM-3.
The molarity can be calculated by dividing the number of moles of solute by the volume of solution in liters. In this case, the molarity would be 2 M (4 mol NaOH / 2 L water).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
6mol/2L
The molarity of 1 mol of Na3PO4 in 2 L of water is 0.5 M. This is calculated by dividing the number of moles of solute (1 mol) by the volume of solution in liters (2 L).
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
There are two ways (at least) to work this. Conceptually, you need 8 bottles of 125mL to make 1L, and, therefore, 16 bottles to make 2L. The HCl gets divided out into those 16 bottles of water, so 6M/16 = 0.4M (you have to round up from 0.375. The data, 6M, has one significant number, so your answer does, too). Another way to think of it is to think of the amount of HCl in terms of moles. 6M means that there would be 6 moles of HCl in each L of water, but we only have 0.125L. To find the number of moles, we multiply 6 moles/L x 0.125L = 0.75 moles (round up to 0.8 moles). The amount of HCl doesn't change, but the amount of the water does, so our final solution has the same 0.8 moles of HCl in 2L of water. We divide moles per L to get molarity, so 0.8 moles / 2L = 0.4 moles/L, or 0.4M. It's always good to get the same answer two different ways :)
1-2l
2 litre of water is approximately 70.2 ounces
0.02
To find the molarity of BaCl₂, first calculate the molar mass of BaCl₂: barium (Ba) is approximately 137.33 g/mol and chlorine (Cl) is about 35.45 g/mol. Thus, the molar mass of BaCl₂ is 137.33 + 2(35.45) = 208.23 g/mol. Next, convert grams to moles: 416.48 g ÷ 208.23 g/mol ≈ 2.00 moles. Finally, the molarity (M) is calculated by dividing the number of moles by the volume in liters: 2.00 moles ÷ 2 L = 1.00 M.