- log(0.2 M)
= 0.70 pH
=======
25g HCl 1 mol 36.46g HCl =.686 mol M=.686 mol/1.5 L=.457M pH= -log(.457) pH= .34
-log10[0.01] = 2
To find the pH of a 0.03 N solution of HCl, we first recognize that HCl is a strong acid that dissociates completely in solution. Since the normality (N) of HCl is equal to its molarity (M) for monoprotic acids, a 0.03 N solution corresponds to a concentration of 0.03 M. The pH can be calculated using the formula pH = -log[H⁺], so pH = -log(0.03) ≈ 1.52.
The pH of a 0.066 M solution of HCl can be calculated using the formula pH = -log[H⁺]. Since HCl is a strong acid, it completely dissociates in solution, so the concentration of H⁺ ions is also 0.066 M. Therefore, pH = -log(0.066) ≈ 1.18.
Adding hydrogen chloride to water the pH decrease.
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a solution containing 6M HCl is 0.
The pH of water decreases after adding HCl due to the increase in hydrogen ions. The resulting pH level depends on the amount of HCl added.
.260 M of HCL, not 260 More than likely correct, but, - log(0.260 M HCl) = 0.6 pH ----------- ( pH can be below 1 )
A 0.1 M concentration of HCl corresponds to a pH of 1.0.
The pH increases because the HCl is becoming less acidic. A pH of 7 is neutral. A pH falls below 7, acidity increases. As pH rises above 7, basicity increases. Diluting HCl means that the HCl becomes less concentrated, and therefore, less acidic. As it becomes less acidic, the pH will become more basic, and thus increase.
The pH of a 0.25 M HCl solution is approximately 0.60. This is because HCl is a strong acid that dissociates completely in water to form H+ ions, resulting in a high concentration of H+ ions and a low pH.
Since HCl is a strong acid it completely dissociates. Therefore [H+] = [HCl] and this case = 0.25 M. pH = -log [H+] = 0.602
The pH of a 0.005N HCl solution is approximately 2.3. This is because HCl is a strong acid that dissociates completely in water to form H+ ions, leading to an acidic pH.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
The pH of 0.05 M HCl is 1.3. HCl is a strong acid that dissociates completely in water to release H+ ions, resulting in a low pH.