- log(0.2 M)
= 0.70 pH
=======
25g HCl 1 mol 36.46g HCl =.686 mol M=.686 mol/1.5 L=.457M pH= -log(.457) pH= .34
-log10[0.01] = 2
Adding hydrogen chloride to water the pH decrease.
The pH of a 0.05 M solution of hydrochloric acid (HCl) can be calculated using the formula pH = -log[H⁺]. Since HCl is a strong acid that dissociates completely in water, the concentration of hydrogen ions [H⁺] is equal to the concentration of the acid, which is 0.05 M. Therefore, the pH is approximately 1.30.
When hydrochloric acid (HCl) is added to a solution with a pH of 7.45, the acidity of the solution increases. HCl dissociates into hydrogen ions (H⁺) and chloride ions (Cl⁻), which lowers the pH as the concentration of hydrogen ions rises. The solution will become more acidic, moving toward a pH closer to neutral (7) or even below, depending on the amount of HCl added. This change can affect various chemical equilibria and biological processes that are sensitive to pH.
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a solution containing 6M HCl is 0.
The pH of water decreases after adding HCl due to the increase in hydrogen ions. The resulting pH level depends on the amount of HCl added.
A 0.1 M concentration of HCl corresponds to a pH of 1.0.
.260 M of HCL, not 260 More than likely correct, but, - log(0.260 M HCl) = 0.6 pH ----------- ( pH can be below 1 )
The pH increases because the HCl is becoming less acidic. A pH of 7 is neutral. A pH falls below 7, acidity increases. As pH rises above 7, basicity increases. Diluting HCl means that the HCl becomes less concentrated, and therefore, less acidic. As it becomes less acidic, the pH will become more basic, and thus increase.
The pH of a 0.25 M HCl solution is approximately 0.60. This is because HCl is a strong acid that dissociates completely in water to form H+ ions, resulting in a high concentration of H+ ions and a low pH.
The pH of a 0.005N HCl solution is approximately 2.3. This is because HCl is a strong acid that dissociates completely in water to form H+ ions, leading to an acidic pH.
Since HCl is a strong acid it completely dissociates. Therefore [H+] = [HCl] and this case = 0.25 M. pH = -log [H+] = 0.602
its PH is 3
The pH of 0.05 M HCl is 1.3. HCl is a strong acid that dissociates completely in water to release H+ ions, resulting in a low pH.