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What is the volume of 1.9 moles of chlorine gas (Cl2) at standard temperature and pressure (STP) 12 L 22.4 L 43 L 81 L?
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. Therefore, the volume of 1.9 moles of chlorine gas (Cl2) can be calculated as follows: 1.9 moles × 22.4 L/mole = 42.56 L. Rounding to the nearest option, the volume of 1.9 moles of Cl2 at STP is approximately 43 L.
What is the volume occupied by 025 moles of chlorine gas?
This volume is 6,197 399 5 at 25 0C.
When determining the molarity of a solution the answer must be in terms of?
The molarity of a solution is determined by dividing the number of moles of solute by the volume of the solution in liters. The answer is typically expressed in moles per liter (mol/L) or Molarity.
How many liters of 17.32g of chlorine gas can be produced?
To calculate the volume of chlorine gas produced, you need to know the molar mass of chlorine and use the ideal gas law equation. First, convert the mass of chlorine gas to moles using its molar mass. Then use the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. Finally, you can solve for V to find the volume in liters.
What is the molarity of the resulting solution obtained by mixing 2.5liter of 0.5M urea solution and 500 ml of 2M urea solution?
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
What is the volume of 2.00 moles of chlorine (cl2) at STP to the nearest tenth of a liter?
At standard temperature and pressure (STP), one mole of gas occupies 22.4 liters. Therefore, the volume of 2.00 moles of chlorine (Cl₂) can be calculated by multiplying the number of moles by the molar volume: (2.00 , \text{moles} \times 22.4 , \text{L/mole} = 44.8 , \text{L}). Thus, the volume of 2.00 moles of chlorine at STP is 44.8 liters.
What is the volume occupied by 025 moles of chlorine gas?
This volume is 6,197 399 5 at 25 0C.
What is the volume of 1.9 moles of chlorine gas (Cl2) at standard temperature and pressure (STP) 12 L 22.4 L 43 L 81 L?
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. Therefore, the volume of 1.9 moles of chlorine gas (Cl2) can be calculated as follows: 1.9 moles × 22.4 L/mole = 42.56 L. Rounding to the nearest option, the volume of 1.9 moles of Cl2 at STP is approximately 43 L.
How can one determine the number of moles present in a solution by utilizing the concentration and volume measurements?
To determine the number of moles in a solution, you can use the formula: moles concentration x volume. Simply multiply the concentration of the solution (in moles per liter) by the volume of the solution (in liters) to find the number of moles present.
What volume is contained of 2.4 moles of chlorine and how do you work it out?
I would assume chlorine gas and standard temperature an atmospheric pressure. Using the ideal gas equation. PV = nRT (1 atm)(X volume) = (2.4 moles Cl2)(0.08206 Mol*K/L*atm)(298.15 K) Volume = 59 Liters of chlorine gas --------------------------------------------
How does 3.45 liters equal in moles?
liter = unit of volume mole = unit of concentration
Calculate the volume of solution needed to dissolve 0.25 moles NaCl to make a 3.0M solution?
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
When determining the molarity of a solution the answer must be in terms of?
The molarity of a solution is determined by dividing the number of moles of solute by the volume of the solution in liters. The answer is typically expressed in moles per liter (mol/L) or Molarity.
How can one determine the number of moles present in a solution by using the molarity and volume of the solution?
To determine the number of moles in a solution, multiply the molarity (in moles per liter) by the volume of the solution (in liters). This calculation gives you the amount of substance in moles present in the solution.
How many liters of chlorine 2 are needed to produce 23.002 moles of NaCl?
The volume is 254,82 L.
What volume of a 0.150 M saltwater solution contains 0.500 g of NaCl?
To find the volume of the solution, first calculate the moles of NaCl in 0.500 g using its molar mass. Then, use the concentration to determine the volume using the formula: moles = molarity x volume. Rearrange the formula to solve for volume, which would be moles / molarity. Substituting the moles of NaCl and the concentration into the formula will give you the volume of the solution.
What volume is occupied of 2.4 moles of chlorine?
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
