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What volume in liters is occupied by 1.5 x 1023 atoms of argon gas (Ar) at STP?
To find the volume occupied by 1.5 x 10²³ atoms of argon gas at standard temperature and pressure (STP), we first need to calculate the number of moles. Using Avogadro's number (6.022 x 10²³ atoms/mole), we find that 1.5 x 10²³ atoms corresponds to approximately 0.25 moles of argon. At STP, one mole of an ideal gas occupies about 22.4 liters, so 0.25 moles of argon would occupy about 5.6 liters.
What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
How many liters of naoh are in 1.3 moles of 3.42 m of naoh?
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
What volume does 0.685 moles of gas occupy at stp?
The volume is approx. 15,35 litres.
How many moles of methane gas occupy 32 L at STP?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. To find the number of moles of methane gas in 32 liters, you can use the formula: moles = volume (L) / volume per mole (L/mole). Thus, the calculation is 32 L / 22.4 L/mole = approximately 1.43 moles of methane gas.
What volume in liters is occupied by 1.5 x 1023 atoms of argon gas (Ar) at STP?
To find the volume occupied by 1.5 x 10²³ atoms of argon gas at standard temperature and pressure (STP), we first need to calculate the number of moles. Using Avogadro's number (6.022 x 10²³ atoms/mole), we find that 1.5 x 10²³ atoms corresponds to approximately 0.25 moles of argon. At STP, one mole of an ideal gas occupies about 22.4 liters, so 0.25 moles of argon would occupy about 5.6 liters.
What volume does 0.50 mole of NH3 at STP occupy?
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
What is the volume of 0.8 moles of chlorine gas at Standard Temperature and Pressure?
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
How many moles of argon gas Ar are present in 5.6 liters of argon gas at standard conditions?
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
How many liters are in 1.84 moles of helium?
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
How to find the volume in liters using molarity and moles in a solution?
To find the volume in liters using molarity and moles in a solution, you can use the formula: volume (L) moles / molarity. Simply divide the number of moles of the solute by the molarity of the solution to calculate the volume in liters.
What volume is occupied of 2.4 moles of chlorine?
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
How do you calculate the number of liters of 3.30 moles of helium at stp?
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
How do you calculate moles from molarity?
To calculate moles from molarity, you use the formula: moles = molarity x volume (in liters). Simply multiply the molarity of the solution by the volume of the solution in liters to find the number of moles present in the solution.
How to find the volume in liters from molarity and moles?
To find the volume in liters from molarity and moles, you can use the formula: volume (L) moles / molarity. This formula helps you calculate the volume of a solution based on the number of moles of solute and the molarity of the solution.
What volume would be occupied by 2 moles of propane gas C3H8 at standard conditions?
1 mole of any gas at STP occupies 22.4 liters. Thus, 2 moles propane will occupy 2 x 22.4 L = 44.8 liters.
At stp how many moles of helium would occupy 1.00l?
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
