You need to know the molar mass of NaCl. Then 10g/molar mass = moles.
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
The number of ions in a 6,58 mole sample of NaCl is 79,25137367812.10e23.
Answer: The mass of NaCl is, 219.15 grams Explanation: Given, Moles of NaCl = 3.75 mole Molar mass of NaCl = 22.99 + 35.45 = 58.44 g/mole Formula used : Now put all the given values in this formula, we get the mass of NaCl. Therefore, the mass of NaCl is, 219.15 grams
1.5g NaCl x (1 mole / 58.5 g NaCl) x (1000 ml / 0.42 mole) = 61.05 ml
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
The mole fraction of NaCl in the solution is calculated by dividing the moles of NaCl by the total moles of NaCl and water. In this case, the mole fraction of 18 mol NaCl in a solution of 100 mol water is 0.15 (18 mol NaCl / (18 mol NaCl + 100 mol water)).
The freezing point of water would decrease if 4 mol of NaCl were added because NaCl is a solute that disrupts the water molecules' ability to form solid ice. Each mole of NaCl added to water reduces the freezing point by approximately 1.86 degrees Celsius. So, with 4 mol of NaCl added, the freezing point of water would decrease by about 7.44 degrees Celsius.
number of moles is mass divided by molecular mass. the molecular mass of NaCl is 58.44g/mol. therefore you need 58.44g to make one mole
convert the .2 kg of NaCl to moles of NaCl.
Determine the mass of 1 mole of NaCl (from the Periodic Table,) then divide that mass by two. NaCl = 58.5g/mol, and 0.5mol would be 58.5/2 = 29.3g
There is one mole of Na⁺ ions for every mole of NaCl. This is because each mole of NaCl dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions in solution.
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
The formula is: NaOH(aq) + HCl(aq) --> NaCl + H2O(l) So the ratio is: 1 : 1 : 1 : 1
The number of ions in a 6,58 mole sample of NaCl is 79,25137367812.10e23.
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.