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How many grams of oxygen are required to complete combustion of 2.75 moles of propane?
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
What is the calculated molar mass of propane gas in grams?
44
How much heat energy is produced when 22 grams of propane is burned in a stove?
To determine the heat energy produced when burning propane, we need to know its heat of combustion, which is approximately 50 MJ/kg. For 22 grams (0.022 kg) of propane, the energy released can be calculated as follows: 0.022 kg × 50,000 kJ/kg = 1,100 kJ. Therefore, burning 22 grams of propane produces about 1,100 kJ of heat energy.
A compound is formed when 48 grams of carbon 8 grams of hydrogen and 68 grams oxygen combine what is the percent by mass of oxygen?
The percentage of oxygen is 54,84 %.
How many moles of in 320 grams of oxygen?
320 grams of oxygen is the equivalent of 10 moles.
How many grams of oxygen are required to burn 100 gram of propane?
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
How many grams of oxygen are required to complete combustion of 2.75 moles of propane?
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
If 15 liters of propane are completely consumed how many grams of carbon dioxide are produced?
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
How many grams of propane did you burn if o.56 grams of water were produced?
7
How many grams of propane react to produce 8.00 grams of water?
Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1
How many grams of propane can be burned by 24 grams of O2?
For complete proper combustion of Propane: C3H8 + 5O2 = 3CO2 + 4H2O The relative atomic weights of a molecule of Propane and Oxygen are: Propane: 3 × C + 8 × H = 3 × 12 + 8 × 1 = 44 Oxygen: 2 × O = 2 × 16 = 32 Thus a molecule of propane is 44/32 = 1⅜ times heavier than a molecule of oxygen; and the same amount (number of molecules) of propane as 24 g of oxygen is 24g × 1⅜ = 33g Each propane molecule takes 5 oxygen molecules, thus: 33 g ÷ 5 = 6 3/5 g = 6.6 g If the combustion produces the poisonous carbon monoxide instead of carbon dioxide: 2C3H8 + 7O2 = 6CO + 8H2O → propane = 33g × 2/7 = 9 3/7 g ≈ 9.4 g A complete answer is thus between 6 3/5 g (6.6g) and 9 3/7 g (9.4 g) depending upon how much carbon monoxide relative to carbon dioxide is produced by the burning - the safe amount is 6.6 g.
What is the calculated molar mass of propane gas in grams?
44
What is the mass in grams of H20 produced when propane is burned?
Let's see. C3H8 + 5O2 -> 3CO2 + 4H2O For every one molecule of propane burned there is four molecules of water produced. Or, this is the actuality. 1 molecule propane (1 mole C3H8/6.022 X 1023)(4 mole H2O/ 1mole C3O8) = 6.64 X 10 -24 molecules water
How much heat energy is produced when 22 grams of propane is burned in a stove?
To determine the heat energy produced when burning propane, we need to know its heat of combustion, which is approximately 50 MJ/kg. For 22 grams (0.022 kg) of propane, the energy released can be calculated as follows: 0.022 kg × 50,000 kJ/kg = 1,100 kJ. Therefore, burning 22 grams of propane produces about 1,100 kJ of heat energy.
How many grams of propane can be burned by 24 g of O?
The answer is 6,61 g.
The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
How many moles of water will be produced if 6.00 grams of propane react?
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
