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Why can't a substance have an empirical formula of NO and a gram formula mass of 45g?
From the Periodic Table
The Atomic Mass of Nitrogen (N) is 14
The Atomic mass of Oxygen (O) is 16
Hence the gram formula mass of NO is 14 + 16 = 30
Now NO under certain circumstances can form N2O2 hence the gram formula mass of N2O2 = (2 x 14) + ( 2 x 16) = 28 + 32 = 60
However the empirical formula is the formula with the lowest ratio of atoms. Hence N2O2 lowest ration is NO # formula mass is 30 .
What else can I help you with?
How the moleculer formula of a compound is calculated if its emperical formula is known?
The gram molecular mass of the molecule must be measured by some independent method such as freezing point depression or boiling point elevation. Then the factor by which to multiply all of the subscripts in the empirical formula to get the molecular formula is the closest integer to the ratio of gram molecular mass to the gram molecular mass of a single unit of the empirical formula.
What steps are used to convert an empirical formula into a molecular formula?
By determining the molecular mass, then dividing the molecular mass by the formula mass of the empirical formula to determine by what integer the subscripts in the empirical formula must be multiplied to produce the molecular formula with the experimentally determined molecular mass.
What is the properly written empirical formula of a compound of molecular formula C6H12 with a molar mass equal to 84.16 gram per mol?
The information about the actual molar mass is superfluous. Given any molecular formula, the corresponding empirical may be obtained by dividing all the subscripts in the molecular by the largest integer that yield an integer quotient for each subscript. In the given formula, the empirical formula is CH2.
If A 2.50-gram sample of calcium metal is heated in a 38.500 gram crucible to form a calcium oxide. if the crucible and product weigh 38.850 g what is the empirical formula for calcium oxide?
Calcium oxide is CaO.
What is the empirical formula of a substance that consists of 3.704g aluminum and 3.295g oxygen?
To find empirical formulas from mass data such as are presented in this question, first convert the masses given to gram atoms by dividing the stated mass for each element by the gram atomic mass of the element. For aluminum, 3.704/26.9815 is about 0.137279; for oxygen, 3.295/15.9994 is about 0.205945. Then divide the larger of these numbers of gram atoms by the smaller to produce a quotient of 1.500. The smallest integers that approximate this ratio are 3 and 2. Therefore, the empirical formula is Al2O3.
What is the molecular formula of a compound with an empirical formula of C4H9 and a gram formula mass of 114 grams mole?
To determine the molecular formula from the empirical formula and gram formula mass, first calculate the empirical formula mass of C4H9 (4 carbons + 9 hydrogens). Then, divide the gram formula mass by the empirical formula mass to find the ratio. Finally, multiply the subscripts in the empirical formula by this ratio to get the molecular formula, which in this case is C8H18.
How the moleculer formula of a compound is calculated if its emperical formula is known?
The gram molecular mass of the molecule must be measured by some independent method such as freezing point depression or boiling point elevation. Then the factor by which to multiply all of the subscripts in the empirical formula to get the molecular formula is the closest integer to the ratio of gram molecular mass to the gram molecular mass of a single unit of the empirical formula.
What steps are used to convert an empirical formula into a molecular formula?
By determining the molecular mass, then dividing the molecular mass by the formula mass of the empirical formula to determine by what integer the subscripts in the empirical formula must be multiplied to produce the molecular formula with the experimentally determined molecular mass.
What is the properly written empirical formula of a compound of molecular formula C6H12 with a molar mass equal to 84.16 gram per mol?
The information about the actual molar mass is superfluous. Given any molecular formula, the corresponding empirical may be obtained by dividing all the subscripts in the molecular by the largest integer that yield an integer quotient for each subscript. In the given formula, the empirical formula is CH2.
What is the molecular formula of a compound given the molar mass of the compound is 162.27 grams and the empirical formula is C2H3?
The gram formula unit mass of the empirical formula C2H3 is twice the gram atomic mass of carbon plus three times the gram atomic mass of hydrogen, or about 27. The nearest integer to 162.27/27 is 6. Therefore, the molecular formula for the compound is C12H18.
If A 2.50-gram sample of calcium metal is heated in a 38.500 gram crucible to form a calcium oxide. if the crucible and product weigh 38.850 g what is the empirical formula for calcium oxide?
Calcium oxide is CaO.
What is a gram of a molecular substance?
A gram of a molecular substance is the quantity that will have a mass of 1 gram.
What is the empirical formula of a substance that consists of 3.704g aluminum and 3.295g oxygen?
To find empirical formulas from mass data such as are presented in this question, first convert the masses given to gram atoms by dividing the stated mass for each element by the gram atomic mass of the element. For aluminum, 3.704/26.9815 is about 0.137279; for oxygen, 3.295/15.9994 is about 0.205945. Then divide the larger of these numbers of gram atoms by the smaller to produce a quotient of 1.500. The smallest integers that approximate this ratio are 3 and 2. Therefore, the empirical formula is Al2O3.
What is the molecular formula of a compound given that molar mass of the compound is 30.04 gram and the empirical formula is NH?
The molar mass of ammonia (NH) is approximately 17.03 g/mol. To get a molar mass of 30.04 g/mol, we need to determine how many times the empirical formula must be multiplied by a whole number. 30.04 / 17.03 ≈ 1.76, so the molecular formula would be NH₂.
What is relative atomic mass and how it is related with gram?
when atomic mass of an element expressed in gram atom is called gram atom mass . and formula is number of gram atom=given mass (in gram) by atomic mass ( in gram )
A compound with the empirical formula SN was found in a subsequent experiment to have a molar mass of 184.32 gmol. What is the molecular formula of the compound?
The empirical formula of SN has a formula unit mass of the sum of the gram atomic masses of nitrogen and sulfur, i.e., about 46.0667. The gram molecular mass given in the problem divided by this formula unit mass is about 4. Therefore, the molecular formula is S4N4.
What is the gram formula for K2SO3?
The gram formula for potassium sulfite (K2SO3) is 158.27 g/mol.
