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Q: How many liters of a 1.5M solution are required to yield 5.0 grams of solute?
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How many grams of solute are contained in 3.5 L of solution that contains 21.7 ppm of SnCl2?

There are 23.5 grams of solute contained for every 1,000,000 liters of solution that contains 21.7 ppm of SnC12. Therefore, there is 0.00008365 grams of solute in 3.5 liters of solution.Ê


How many grams of solute are required to make a 918 mL solution of sodium hydroxide with a concentration of 0.4922 M?

Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================


Concentration is always measured in grams of solute divided by liters of solution?

no ; false


What is the volume of 3.0 M solution of NaCl made with 526g of solute?

Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------


How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?

Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed


How many grams of sodium chloride is in 0.40 moles?

Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============


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What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?

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What is the molarity a 500.0 ml solution containing 0.75 moles of solute?

Molarity = moles of solute/Liters of solution Without the solute name the mass ( 8 grams ) does no good. Mass of solute (1 mole/molar mass of solute) = moles solute ----------------------then use Molarity equation. ( remember convert to liters )


What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?

Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------


How many grams of NaOH are in 350 mL of a 5.7 M NaOH solution?

Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------


What is the molarity of a solution if 255 grams AgNO3 is dissolved in 1500 mL of solution?

Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------