3.33
Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------
To calculate the grams of solute needed to prepare a solution, you can use the formula: moles = Molarity x Volume (in liters). First, convert the volume to liters (250.0ml = 0.250L). Then, multiply the molarity (0.125 M) by the volume in liters to get the moles of CuSO4. Finally, multiply the moles by the molar mass of CuSO4 (159.61 g/mol) to get the grams needed. So, grams of CuSO4 needed = 0.125 mol/L x 0.250 L x 159.61 g/mol = 5.00 grams.
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The solubility of a substance at a given temperature can be expressed as the maximum amount of solute that can dissolve in a solvent at that temperature, typically in grams of solute per 100 mL of solvent. It can also be expressed in terms of molarity or molality, which represent the concentration of the solute in the solution.
The conversion from grams to liters depends on the density of the substance. To convert 40 grams to liters, you would need to know the density of the specific material. The formula for this conversion is: volume (liters) = mass (grams) / density (grams per liter).
Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================
To calculate the grams of solute in the solution, first convert ppm to g/L by multiplying by the density. The density of a SnCl2 solution is approximately 2.3 g/mL. Then, convert L to mL by multiplying by 1000. Finally, multiply the concentration in g/L by the volume in mL to find the total grams of SnCl2 in the solution.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
To determine the grams of solute in a solution, you need to know the molar mass of the solute. Multiply the molarity of the solution by the volume in liters to get the number of moles, then multiply by the molar mass to get the grams. In this case, for 2 moles of solute in 500 cm3 (which is 0.5 L), the mass of the solute would be 2 moles/L * 0.5 L * molar mass of solute in g/mol.
Molarity = moles of solute/Liters of solution Without the solute name the mass ( 8 grams ) does no good. Mass of solute (1 mole/molar mass of solute) = moles solute ----------------------then use Molarity equation. ( remember convert to liters )
200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.
To make a 2.13 M solution of KBr, you need to determine the number of moles of KBr required using the formula Molarity = moles of solute / volume of solution in liters, then calculate the mass of KBr needed using its molar mass. Once you have the mass of KBr, you can add it to the water to prepare the solution.
To calculate the amount of solute needed for making molar solutions, you can use the formula: Amount of solute (in grams) molarity (in mol/L) x volume of solution (in liters) x molar mass of solute (in g/mol) This formula helps determine the quantity of solute required to make a specific molar solution based on its concentration and volume.
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
To create a 12% weight/volume (w/v) solution, you need 12 grams of solute for every 100 mL of solution. Therefore, for 100 mL of a 12% w/v solution, you would require 12 grams of the solute.
Concentration can be measured in various units depending on the solute and solvent. Common units include molarity (moles of solute per liter of solution), mass/volume percent (grams of solute per 100 mL of solution), and molality (moles of solute per kilogram of solvent). The appropriate unit depends on the specific experimental conditions and the properties of the solute and solvent.
Molarity is calculated by dividing the moles of solute by the liters of solution. The formula is: Molarity (M) = moles of solute / liters of solution. This is a common way to express the concentration of a solution.