Calculus

In a sense, yes. This type of reflection, in which a function is reflected over both the x and y-axes, is a possible characteristic of odd functions and is known as origin reflection, or reflection about the origin.

-3

It is impossible to answer the question because a triangle cannot be specified with only two lengths.

6x = 3/5

30x = 3

x = 3/30

x = 1/10

5x2 + 8x = 7

5x2 + 8x - 7 = 0

This cannot be factorised so the solutions need to be determined using the quadratic formula

The solutions are {-8 ± sqrt[82 - 4*5*(-7)]}/(2*5)

= {-8 ± sqrt[64 + 140]}/10

= {-8 ± sqrt[204]}/10

= -2.22829 and 0.62829 (to 5 dp)

4 x 2 + 4 = 12

x = 4

4x+5 = 8

Subtract 5 from both sides:

4x = 3

Divide both sides by 4 to find the value of x:

x = 3/4 or 0.75

It doesn't matter what unit you use to measure the physical length of the

pendulum. As a matter of fact, it doesn't matter what unit you use to measure

the duration of its period either. If both are at rest on the same planet, then

the penduum with the longer string has the longer period. Period!

x - 6

Rechardsons equation

5x+2=2x-10

x=-4

y8 divided by y3 = y5

3x-3y

z = 5

Whatever the number you might think of, you can always add 1 to it. So, no, numbers don't come to an end. It's called infinity. or google

It looks like a parabola which looks like a U shape.

y = x2 + 3

100*(100-3)/2 = 4850

There is no such thing as a milimeter. Millimetre, yes. Even millimeter (if you happen to be American).

Next, there are no units given for 9 x 12. It is, therefore, impossible to tell whether you mean 9 nanometres * 12 nanometres or 9 light years by 12 light years or something in between those - or possibly beyond.

Finally, a millimetre is a measure of distance in 1-dimensional space. 9 x 12 appears to be a measure in 2-dimensional space. A measure in 1-d cannot be converted to a 2-d measure.

I recommend that you reconsider your question and ask it, providing relevant units etc, and in a way that makes some sense.

There are a number of possible solutions which will have x=2 and y = 10 as solutions but many of them will also allow other solutions.

One possibility, with a unique solution, is (x-2)2 + (y-10)2 = 0

4

eg: x = 1, y = 6; x = 2, y = 10; x = 3, y = 14 etc

logx(3) = log10(7)

(assumed the common logarithm (base 10) for "log7")

x^(logx(3)) = x^(log10(7))

3 = x^(log10(7))

log10(3) = log10(x^(log10(7)))

log10(3) = log10(7)log10(x)

(log10(3)/log10(7)) = log10(x)

10^(log10(3)/log10(7)) = x

No.

Kw is a measure of power with units [ML2T-3] whereas 1.0*10-14 is a pure, dimensionless number. There can be no equivalence because the dimensions do not match.

You find two numbers whose sum is -7 and product is +10.

x2 - 7x + 10 = (x - 2)*(x - 5)