Probability

food

Extreme values. They might also be called outliers but there is no agreed definition for the term "outlier".

as many times as it lands on its tail.

-0.38532

Answers.com is a good site for statistics questions.

Each number is 15 subtracted from the preceding number.

Assuming as the die is rolled, and its a 6-sided die (1, 2, 3, 4, 5, & 6), each number has a 1/6 probability of being rolled. The probability of any number being rolled is 1/6 and the probability of not rolling that number is 5/6. Something that has only 2 outcomes, such as boy & girl or heads & tails, will have the 50 50 probability.

10cm is 100,000um. 100,000/20 is 5000 magnification

It depends on other restrictions placed on the problem, the main one of which is how many colours you can have on one uniform and their arrangements.

Assuming each uniform is one colour, the problem is trivial. There are 7, one uniform in each colour.

If each is split into a shirt and trousers, there are then 49 combinations, each one with a different combination.

This can clearly be extended allowing infinitely many coloured patches, giving rise to infinitely many different uniforms.

If however you place the restriction that no uniform may contain the same colour more than once, there are nPr uniforms, where n is the number of colours available (7) and r is the number on each uniform. The greatest number of uniforms under this system is obtained with either 6 or 7 coloured patches, for 5040 different uniforms.

Another restriction would be that you consider a uniform with, for example, red trousers and a blue shirt, to be the same as one with blue trousers and a red shirt and still disallow double colours. In which case there are only nCr uniforms, or a maximum of 35, from 4 different patches.

In short there are arbitrarily many restrictions that could be placed on the uniforms' designs, so any number of possible uniforms could be selected (in theory) by setting the right restraints.

Thankyou for your question, it was quite an interesting distraction and helped me to remember some statistics maths that I've haven't used for a few years. If you were looking for a useful answer though, I apologise for not providing one.

Two.

If N is odd, the probability is 0.

If N is even, suppose N=2M

then the probability is 2MCM*(1/2)2M which approaches 0 as N (or M) increases.

For N = 10, Prob = 0.1762

For N = 20, Prob = 0.1254

For N = 30, Prob = 0.1026

For N = 80, Prob = 0.0630

A probability of 16% is about 1 in 6. As with so many things expressed with probability we tend to be subjective in deciding whether this is likely or not. One factor might be loss. If I have a 1 in 6 chance of being two minutes late for a routine weekly meeting to take time for a much needed coffee I might take the risk. If I have a 1 in 6 chance of being flattened by a snowplow hurrying to cross a road when I have nothing better to do then I might be happy to wait.

um no one would wana watch that show i would rather watch a program on the tree octopus

They probably don't have Jesus in their hearts, souls, or minds.

7

5 out of six

that number is so large that it is off the charts

I'm pretty sure it was a knife or something dangerous like that!?

If you toss the coins once only, it is 1/4.

three sixths

BALANCE

9/11 happened in 2001.

The answer depends on the number of candidates.

LOYAL FRIEND

Monge's abilities brought him to the attention of Napoleon and they were to become good friends, though he was more than twenty years older than Napoleon. In 1798, Napoleon attacked Alexandria and Monge was anxious to join in the attack. Napoleon would not allow it: after all, Gaspard was 52-years-old! Nevertheless, Gaspard left France but his boat was attacked - he defended courageously until Napoleon had to leave his main force to save his friend.

Napoleon and Monge returned to France and the story goes that Gaspard had worn the same clothes for the entire trip. Monge continued to be friends with Napoleon, making himself a political victim of Napoleon's enemies - the Bourbons.

Under those conditions, it would be advisable to sit down while

working on the problem, in order to avoid painful distractions.