Statistics

If the pearson's skew is between 0.0 and 0.49, then it is a normal or non-problematic distribution. If it is above .50, then it is not a normal distribution.

In appearance:

The data should be symmtrical; the mode and median should be very close to the mean; around 65 % of the observations should be withing one standard deviation (SD) of the mean; 95% of observations with 2 SD of the mean and almost all within 3 sd.

Better evidence can be provided by the chi-square or Kolmogorov-Smirnoff goodness-of-fir tests.

There may also be evidence from the nature of the data. For example, the means of samples will be closer to being normally distributed (Central Limit Theorem) than the individual observations.

It is 1/12.

A line or bar graph is ideal for showing trends.

That really depends on the specific circumstances - including the level of confidence you want to achieve.

This only works for y=mx, not y=mx+c.

theta = tan(m)

eg y=x theta = tan(1)

.: theta = 45

(23,56)

No. 11 decimetres = 1.1 metre is closer. And 1.01 m is closer still. 1.001 m is even closer and so on.

Plain and simply YES

Yes. It should reduce the variance.

Easy don't know

It is actually very simple, just take 10 to the square root of four.

10^4

Call the first integer "n". In this case, the integer after that is "n + 1". That would make the equation:

n + (n + 1) = 1279

If you solve this equation for "n", "n" would stand for the first of the two numbers.

7.7% or 4/52

It is 15/50 = 0.3

45% = 0.45

0

The answer is the same as all of the base-three numbers that have less than seven digits, which is 36 or 729. However, that includes every possible order of the same 6 digits.

90

There are 12,500 of them and I am not going to list them. One of them is 200000.

• i don't know if you know it please help me

50%

Yes.

4500

Not very