If you mean ((-2) x (-6)) - (3 x (-21)) then it equals 75.
Hope this helps!
If: y = 4x^2 -2x -1 and y = 3x-2x^2 +5
Then: 4x^2 -2x -1 = 3x -2x^2 +5
Transposing terms: 6x^2 -5x -6 = 0
Dividing all terms by 6: x^2 -5/6 -1 = 0
Completing the square: (x-5/12)^2 = 169/144
Square root both sides: x-5/12 = -13/12 or 13/12
Adding 5/12 to both sides: x = -2/3 or 3/2
Substitution of x into original equations intersections are at: (-2/3, 19/9) and (3/2, 5)
How many years would it take to count out 60 billion dollars?
well it dapends how fast u count but i can count out 120 in a min so 60 billion/120=ur aunswer
How do you solve x raised to the power of 36?
x raised to the power 36 is x36. Without a value for x, there is nothing to solve!
Where is the center of the circle given by the equation x - 3 2 plus y plus 2 2 equals 9?
(3, -2) You find the center by taking the opposite of the numbers added to the X and to the Y.
What is the range of y equals negative 2x squared plus x?
y = -2x² + x
y = -2 [ x² - (x/2) ]
y = -2 [ x² - (x/2) + (1/4) ] + (1/2)
y = (1/2) - 2[ x - (1/2) ]² ≤ (1/2)
Hence, the Range of y is : -∞ < y ≤ (1/2).
It can be written as the interval ( -∞, 1/2 ]. ........ Ans.
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X2 plus 2X equals 8 completing the square?
I think this is how you do it:
x2+2x = 8
x2+2x+(1/2*(2))2 = 8 + (1/2*(2))2
x2+2x+1=8+1
(x+1)2 = 9
SQ.ROOT [(x+1)2 = 9]
x+1 = 3 and x+1 = -3
so,
x=2 and x=-4
How do you isolate y in x plus 2y equals 12?
subtract x from both sides
divide each term by 2.
y=-1/2 x+6
What is the ordered pair of 6x-8y plus 6 equals 36 6y equals 4x-24?
It is: x = -3 and y = -6 or as (-3, -6)
How do you solve this equation -6 equals x over 12?
-6=x/12
The first and only step is to multiply both sides by 12. This gives us x on the right hand side and -6x12 on the left, which simplifies to -72
Thus -72=x
And so x is negative 72.
What is the volume of 30 inches x 30 inches?
The volume is zero.
"30 inches by 30 inches" is a flat, square place, on a table, a piece of paper,
or the ground. You can't put anything in it because it has no "in" .