Calculus

1/x4

There is an app called the "character viewer"; see if you can find an infinity sign there.

pretty

5.59234073

That depends on the values of 'z', 'y', and 'x'.

(1) Find the x-intercepts (by setting y=0 and solving for x).

(2) Find the y-intercepts (by setting x=0 and solving for y).

(3) OPTIONAL: Check for symmetries. If a point (x,y) is on the graph, is the point (-x,y) also on the graph (that is symmetry about the y-axis)? Is the point (-x,-y) on the graph (that is symmetry about the origin)? There are many kinds of symmetries.

(4) Check for vertical asymptotes--normally you would set the denominator ONLY equal to zero and solve for x, but this equation does not have any fractions, so don't worry about this step.

(5) Check for horizontal asymptotes--what is the limit of the equation as x approaches infinity? Negative infinity? (In this example the limit will not exist; the graph will go toward infinity as x gets bigger.)

(6) Use the first derivative test to find the maximums and minimums, as well as to determine the intervals where the graph increases and decreases.

(7) Use the second derivative test or concavity test to find points of inflection and/or concavity.

(8) Wherever the behavior of the graph is still unclear, simply plug in some test values for x and see what you get for corresonding y values.

Subtract 7 from each side of the equation: 2x = 8

Divide by 2: x = 4

f-18=48-10f 11f-18=48

11f=66

f=6

This is a classic calculus problem.

V=s3

dV=3s2 ds

ds = dV/(3s2)

dV = 9 cm3/s

s=4 cm

ds = 9/(3*64) = 3/64 cm/s

SA=6s2

dSA=12s ds

dSA=48*(3/64) cm2/s = 9/4 cm2/s = 2.25 cm2/s

Velocity is basically speed. Take the distance traveled and divide by the time. (Distance/Time).

common units are:
Miles per Hour (MPH)
Meters per second (m/s)
Kilometers per hour (KPH)
feet per second (fps)

The answer depends on what information is given.

11

8.016 comes first. Think of it without the decimal points.

When vectors are added together, the result is still a vector.
Here's a way of looking at it: Person A (vector A) walks one mile north, and Person B (vector B) walks two miles east. If a different person, Person C (vector C, the result of adding vectors A and B) did both, Person C would walk one mile north then two miles east. Since the shortest distance between two points if a line, you can draw a path from where you started to where you ended up after both vectors.
If you drew these three vectors (one unit up, two units right, and the resulting vector), with one original vector's end point at the other vector's start point, and a third vector leading from the start point of the first to the end point of the second, you should see a triangle.
This can also be applied to the addition of more than two vectors.

e= energy

m=mass

c=speed of light

lim x->3 1/(x-3)

First substitute 3 in for x, this gives 1/0 which is undefined and not allowed
So, next set up limits from the left and right sides


From the left
lim x->3- 1/(x-3) (the - is the symbol for from the left), this gives 1/a very small neg
1/a very small neg= -infinity


From the right
lim x->3+ 1/(x-3), this gives 1/a very small positive number
1/small pos=infinity


The left should equal the right; since it does not, there is an asymptote at x=3

1066 = Year of the Battle of Hastings

3x + y

(3, 1)

There really is no answer to your question. In order to provide an answer there would have to be another side to the equation ex: 2y + 6x = 12 and also another equation with the same variables ex: x + y = 8, or another side to the equation with one of the variables given ex: x = 4 find what y equals if x + y = 8.

x2+10x+25

If x has the power 2 then you want the integral of x2, I think.

When you integrate this you get : x3/3 , plus a constant.

With great difficulty because in the absence of an equality sign it has no solutions but it is just some kind of algebraic expression.