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Calculus

The branch of mathematics that deals with the study of continuously changing quantities, with the use of limits and the differentiation and integration of functions of one or more variables, is called Calculus. Calculus analyzes aspects of change in processes or systems that can be modeled by functions. The English physicist, Isaac Newton, and the German mathematician, G. W. Leibniz, working independently, developed calculus during the 17th century.

25,068 Questions

What are the first 120'000 digits of pi?

I don't think people know that much of pi, but the first 120 are:

3.14159265358979323846264338327950288419716939937510582097494459230

7816406286208998628034825342117067982148086513282306647.

I've posted a link below that displays a million digits of pi.

Can someone prove that 2k 2k 1-1?

You can prove that 2K,2K,1-1 by first determining that the integer N can be written in the form of N=2K.

What are the co-ordinates points of y equals 2x plus 1 equals?

Simply substitute any value for y, solve for x for points along the line Y = 2X + 1

Derive EOQ appllied to production order?

Q size to order : obej. to find best of Q to minimize the cost

K:setup cost

c:cost of one unit

h: holding cost for one unit per one unit period of time

landa = demand rate

T cycle length = Q/landa

The cost is = order cost + cost of all unit ordered + average holding cost

C=K+cQ+(ThQ)/2

we divided all over time to be per unit time

so the average cost is :

G= (K+cQ)/T + (hQ/2)

replace T=Q/landa

G= ((K+cQ) / (Q/landa)) + (Qh/2)

then by manipulating

G= ((K* landa )/Q) + ( landa* c)+ (hQ/2)

this formula represent period setup cost , period purchases cost and period holding cost respectively.

because we want to find the minimize this formula gives we need to take the derivative -using calculus- to respect of Q:

G' = (- k *landa / Q^2) + h/2 - give min and max -

taking 2nd derivative

G'' = (2*k*landa)/Q^3

for Q>0 => G''>0 => G' is the min

having G' = 0

G' = (- k *landa / Q^2) + h/2 = 0

( k *landa / Q^2) = h/2

=> Q^2= (2*k*landa)/h

by taking square root of both sides

Q# (EOQ)= sqrt [(2*k*landa)/h]

How do you find an angle of a right triangle?

you need to have at least 2 values of the lengths of the triangle

and then you can find the angle by sine, cosine or tangent formulas

you may try this online calculator for right triangles.

http://www.rillocenter.com/calculate/trigonometry.html

What is the parabala of y equals -7x2-4x plus 4?

This parabola opens downward. It rises from negative infinity, peaks within a few units of the origin,

then heads back down to negative infinity.

The following numbers are all rounded. Nothing comes out even.

-- The maximum value of 'y' is 4.571429, at [ x = -0.2857 ].

-- The parabola crosses the x-axis at [ x = -1.0938 ] and [ x = 0.5224 ].

If -x plus 25 equals 100 what does -x equal?

-x+25 = 100

-x = 100-25

-x = 75

x = -75

Substituting the value of x into the original equation:

- - 75+25 = 100

Remember that in maths a - - is equal to a +

Y equals x squared plus 4x plus 11?

Y = x2 + 4x + 11

OK. That's very interesting.

Is there a question ?

What does it mean when a capacitor is blinking all zeros?

It means you have a very interesting capacitor. Did you mean to say calculator?

How do you solve complicated cases of quadratic equations?

The standard form of a quadratic equation in one variable is ax^2 + bx + c = 0.

There is a new solving method, called Diagonal Sum Method (Amazon e-book 2010) that can directly give the 2 real roots without factoring. It uses a Rule of Signs for Real Roots and a Rule for the Diagonal Sum. To know how to proceed with this new method, please read the article:"Solving quadratic equations by the Diagonal Sum method" on this Wiki Answers website.

Depending on the values of the constants a and c, solving quadratic equations may be simple or complicated.

A. When a= 1. Solving by the new method is simple and doesn't need factoring.

B. When a and c are prime/small numbers, the new method directly selects the probable root pairs from the (c/a) setup. Then it applies a simple formula to calculate all diagonal sums of these probable root pairs to find the real root pair.

C. Complicated cases: When a and c are large numbers and contains themselves many factors.

In these cases, students are advised to write down the (c/a) setup. The numerator of the setup contains all factors-sets of c. The denominator contains all factors-sets of a. Next, the new Diagonal Sum Method transforms a multiple step solving process into a simplified one by doing a few elimination operations.

Example 1. Solve: 45x^2 - 74x - 55 = 0.

Solution. Rule of sign indicates two roots have opposite signs. All-options-line:

Numerator. Factors-sets of c = -55: (-1, 55) (-5, 11)

Denominator. Factors-sets of a = 45: (1, 45)(3, 15)(5, 9)

Now, you may use mental math to calculate all diagonal sums and find the one that fits. However, the best way is to transform the c/a setup into its simplest form by doing a few eliminations.

First, eliminate the pairs (-1, 55)/(1, 45)(3, 15) because they give large diagonal sums, compared to b = 74. The simple remainder c/a: (-5, 11)/(5, 9) leads to the unique root pair: (-5/9 & 11/5). Its diagonal sum is -25 + 99 = 74 = -b. The two real roots are: -5/9 and 11/5.

Example 2. Solve: 12x^2 - 272x + 45 = 0.

Solution. Both roots are positive. Write down the (c/a) setup.

Numerator: (1, 45) (3, 15) (5, 9)

Denominator: (1, 12) (2, 6) (3, 4)

First, eliminate the pairs (1, 12) and (3, 4) because they give odd-number diagonal sums, while b is and even number. Next, look for a large diagonal sum (-272). The fitted (c/a) should be (1, 45)/(2, 6) that give 2 probable roots-sets: (1/2 & 45/6) and (1/6 & 45/2). The diagonal sum of the second set is 270 + 2 = 272 = -b. The 2 real roots are: 1/6 and 45/2.

Example 3. Solve: 45x^2 - 172x + 36 = 0.

Solution. Both roots are positive. Write down the (c/a) setup.

Numerator: (1, 36) (2, 18) (3, 12) (6, 6)

Denominator: (1, 45) (3, 15) (5, 9)

First, eliminate the pairs (1, 36) (3, 12) since they give odd-number diagonal sums (while b is even). Then, eliminate the pairs (6, 6)/(3, 15) because they give diagonal-sums that are multiples of 3. This would make the given equation be simplified by 3. The remainder probable root pairs are: (2, 18)/ (1, 45) and (2, 18)/(5, 9). The second c/a gives 2 probable real roots-sets (2/5 & 18/9) and (2/9 & 18/5). The second set has as diagonal sum: 172 = -b. The 2 real roots are 2/9 and 18/5.

Example 4. Solve 24x^2 + 59x + 36 = 0.

Solution. Both roots are negative. Write the (c/a) setup.

Numerator: (-1, -36) (-2, -18) (-3, -12) (-4, -9) (-6, -6)

Denominator: (1, 24) (2, 12) (3, 8) (4, 6)

First, eliminate the pairs (-2, -18)(-6, -6)/(2, 12) (4, 6) because they give even-number diagonal sums (while b is odd). Then, eliminate the pairs (-1, -36) (-2, -18)/(1, 24) since they give too large diagonal sums (b = -59). The remainder c/a is (-4, -9)/(3, 8) that gives the 2 real roots: -4/3 and -9/8.

Comments. We see that the new Diagonal sum method can transform a multiple step solving process into a simplified one by doing a few elimination operations. With practices and experiences, students will feel the above operations routine and they can surely find the real root pair that fits. It may be simpler if you solve these complicated equations by the quadratic formula with a calculator. However, performing the above operations helps fulfill the goal of learning math, that is to improve logical thinking and deductive reasoning. It would be a boring hard work if you have to solve these complicated equations by the quadratic formula without a calculator, during some tests/exams for examples.

What is x squared plus 20x?

The only thing you can do is to rewrite it as x(x + 20). For anything else, you need the value of x.

Is there an official number for sin tan and cos?

No, they are functions associated with angle values. The function values are dependent on the input angle.

What is difference between in bound and out bounds in BPO?

An outbound bpo is one in which bpo agents make outbound calls to customers on behalf of a business or client. Calls made from the center can include telemarketing, sales or fund-raising calls, as well as calls for contact list updating, surveys or verification services. An inbound bpo is one that exclusively or predominately handles inbound calls (calls initiated by the customer) rather than outbound calls. A bpo may handle either only inbound or outbound calls or might deal with a combination of the two.

Which is easier to graph 3x 4y equals 8 or y equals -0.75x plus 2?

They are the same equation just written differently so they are both easy to graph.