Electrical Engineering

Let C1=0.05F

& C2=0.025F, C1 & C2 are in series

Let the equivalent capacitance will be C

than 1/C = 1/C1 + 1/C2

1/C = 1/0.05 + 1/0.025 = 20 + 40 = 60F

hence C= 1/60 = 0.0166667 F

A multimeter combines the functions of an ammeter, voltmeter, and ohmmeter and, so, can be used to measure current, voltage, and resistance by selecting the appropriate scale/setting.

Red Blood Cells, White Blood Cells and the Cell Wall are three types of primary cells. no noob we are talking about batteries if u dont know dont say. alkaline would be one main type but for exaples u have the aa, aaa, and so on.

The use of the micro- prefix for capacitance, i.e. microfarads, is common because the farad is a very large unit of capacitance and we don't normally use capacitors in that range of value.

Feeders are conductors which connect the consumers with the sub-station. Tapings to feed current to the consumers are NOT taken from the feeders. Therefore, its current loading remains the same along its entire length. Instead, Tapings to each consumers are taken from the DISTRIBUTORS, whose current loading varies along its length.

Since the current in a resistor is the same as the current in the leads/wires on either side of the resister, I might use a clamp meter such as an Amprobe to measure current, if the current was alternating (AC). Otherwise, I would have to break one of the leads and insert an ammeter or a multimeter with an amp setting into the circuit. Afterwards the broken connection would have to be repaired.

Load on an electrical system is the power being drawn from the system. All electrical devices like fridges, heaters and light bulbs have an associated power usage capacity measured in Watts(W). Thus, we have a 60W light bulb. When these devices are all connected to an electricity network their combined power usages is load on the system.

Load can also refer to usage of say a house or factory. Often this will vary over time depending on what devices are turned on inside.

The opposite of load is generation, also measured in Watts. A power plant's generation capacity is so great it is usually measured in Mega Watts (MW) or a million watts. The generation and the load on a system have to be balanced otherwise the system becomes unstable. This can lead to load shedding and blackouts.

K=(voltmeter range*ammeter range*power factor)/wattmeter range

The return path in a delta connection is simply the other hot's. The three load windings are connected between AB, BC, and CA. In essence, each phase conductor is supplying power to two different phase windings. Assuming the winding currents are balanced, you can calculate the phase conductor currents by multiplying the winding currents by the square root of 3. (1.732)

Its not that different from the return path for a single phase 240V appliance, such as a hot water heater, in a 120/240V split phase system. Neutral is not involved. The current flows from hot to hot.

that is to reduce the cost of the power plant....

Improving power factor(increasing the ration active/apparant power morethan 0.8) will increase the efficiency of uer system. Improving power factor denotes eleminating the recative power(which do no average work).... If u have more capacitive parts in uer system, the power you may need be really high when the capacitor is charging. But as it is in an a.c. system, used energy will be released and hence the average energy consumption of the cap is null. As in one instance iot absorbes energy, the electricity distributers must be able to generate such an high power which will incrrease their cost(eventhough the absorbed energy will be released)!!!

Just by reducing the the reactive power, you can reduce the enery absorption. However to do so, you may have to use caps/inductors whcich will cost you a lot.

Generally, electricity distributors say, "You must not reduce uer power factor than 0.8"... In some countries, distributors pay for the factries if there power factor is higher than a cirtain value(0.95)....

-R-

advantages is:1) we are able to analyse relationship between current and voltage.2)able to give the resistance applied in circuit.there is only one limitations that is it can change its value if the circuit is left on for long time.thankyou:).

'Force' isn't measured in volts. Potential and potential difference are measured in volts.

the highest transmission volatage in India is 765kV ac. The highest voltage in the case of DC transmission is +/- 600 kV.

S = Apparent Power

P = Real Power [Negative for supplied power, positive for absorbed power]

Q = Reactive Power [Positive for lagging or inductive loads, negative for leading or capactive loads]

Fp = Power Factor [Specified as lagging or leading for inductive or capacitive loads respectively]

V = Voltage

I = Current

* = (Conjugate)

< = 'At an angle of'

For DC cases:

|P| = P = V x I = V^2 / R = I^2 x R

For AC cases:

S = V x I* = |S| < arccos(Fp)

|S| = |V| x |I|

|P| = |S| x Fp

|Q| = sqrt(|S|^2 - |P|^2)

If the magnetic field applied to a magnetic material is increased and then decreased back to its original value, the magnetic field inside the material does not return to its original value. The internal field 'lags' behind the external field. This behaviour results in a loss of energy, called the hysteresis loss, when a sample is repeatedly magnetized and demagnetized. The materials used in transformer cores and electromagnets are chosen to have a low hysteresis loss. Similar behaviour is seen in some materials when varying electric fields are applied (electric hysteresis). Elastic hysteresis occurs when a varying force repeatedly deforms an elastic material. The deformation produced does not completely disappear when the force is removed, and this results in energy loss on repeated deformations.

35 to 70

It depends on the mix of concrete you are using. A basic 1-2-3 mix is 5 1/2 cubic feet of portland cement (a wheelbarrow, depending on its size, holds 1/2 to 1 cubic feet), 11 cubic feet of sand, and 16 1/2 cubic feet of stone (called aggregate) from 1/2 to 1 inch in size each. To this is added about 12-15 gallons of water.(1 1/2 to 2 cu.ft.). This will make just a little less than 1 cubic meter of concrete.

A weaker mix for basic work not needing structural strength a 1-2-3 mix of 1 part stone, 2 parts cement and 3 parts sand can be used, this would require a bit less than 1 part water.

A stronger mix of 1 part cement, 1 1/2 parts sand and 3 parts stone with about 1/2 part water is good for heavy duty concrete work. Stone will increase the strength of concrete and sand will weaken it. Using too much or too little water in the mix will weaken it as well. Additionally, concrete with too much water or too little cement tends to shrink and crack as it sets. The amount of water to use is mainly dependent on the cement in the mix. There should be at least half as much cement as sand in any mixture. The amount of stone to use should be between 1/4 and 3/4 of the total mixture. Grouts and mortars use no stone and may add limestone as an additional binder. These should not be used for structural concrete, but can be used for foundation pointing, bolt anchoring or mortaring brickwork.

Batteries in series makes the voltage additive. If the bulb is only rated at a specific voltage and you double the voltage the bulb will glow brighter but its life span will be shortened. Batteries in parallel will keep the voltage at the same level as a single battery but the endurance drain of the batteries will be doubled. Example, if a battery is drained of power, with a bulb being left on continuously, in one hour then two batteries in parallel would allow the bulb to glow for two hours before the batteries were drained of power.

The application of engineering knowledge to the development of medical products. The engineering disciplines involved range from the traditional engineering fields to software and genetic engineering. The field is broken up into a number of specialty areas as varied as the biological and engineering fields from which they spring.

Single bus is used in smaller, less important substations. A fault on the bus requires tripping of all lines into the bus. When higher redundancy is necessary, ring and breaker and 1/2 schemes are used. These are the three most common.

rms. dat means Vp-p will be 325V.

You reduce voltage in a DC circuit with a resistor. If the power demands are high, however, you may need a switching voltage regulator.

Voltage = resistance X current abbreviated,
V = C * R


If you halve the voltage of the current, then the other side of the equation must also be halved; therefore, you get:


(1/2)V=(1/2)(C*R)


which is the same as:


(1/2)V=(1/2)(C)(R)


which means that either the current or the resistance must be halved as well, and because the resistance stays the same, then the current is halved.